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2 years ago

Which of the following water molecules exists in the greatest abundance?

Physics

1 answer:

aliina [53]2 years ago

7 0

Answer:

d. H216O

Explanation:

Hello,

Water is a chemical compound which has two hydrogen atoms and one oxygen atom.In solid state, it is ice where as in gas state, it is steam.Hydrogen and oxygen atoms in water molecule form polar covalent bonds formed through hydrogen bonding. Oxygen has three isotopes to remember ; H2160, H2180 and H2170. Sea water for example has approximately 99% H2160 and less than 0.5% H2180.

Evaporating waters releases more H2160 to the atmosphere than H2180.In areas where polar ice takes time to melt, the oceans are contantly depleted of H2160 until it melts to return to the water bodies and maintain balance.This shows that the water molecules that exists in greatest abundance is H2160.

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Heat is extracted from a certain quantity of steam at

vodomira [7]

Answer: $v=2452.91 m/s$

Explanation:

Given

initially steam is at $100^{\circ}C$ and converted to $0^{\circ} C$ ice

Let m be the mass of steam

latent heat of fusion and vaporization for water is

$L_f=3.33\times 10^5 J/kg$

$L_v=2.26\times 10^6 J/kg$

Heat required to convert steam in to water at $100^{\circ}C$

$Q_1=m\times L_v=m\cdot 2.26\times 10^6 J$

Heat required to lower water temperature to $0^{\circ}C$

$Q_2=m\times c\times \Delta T$

$Q_2=m\times 4.184\times (100)$

$Q_2=4.184m\times 10^5 J$

Heat required to convert $0^{\circ}C$ water to ice at $0^{\circ}C$ is

$Q_3=m\times L_f$

$Q_3=m\times 3.33\times 10^5=3.33m\times 10^5 J$

$Q=Q_1+Q_2+Q_3$

$Q=(2.26+0.4184+0.33)m\times 10^6 J$

$Q=3.0084m\times 10^6 J$

So this energy is equal to kinetic energy of bullet of mass m moving with velocity v

$Q=\frac{1}{2}mv^2$

$3.0084m\times 10^6=\frac{1}{2}mv^2$

$v^2=3.0084\times 2\times 10^6$

$v=2.452\times 10^3 m/s$

$v=2452.91 m/s$

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