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IRINA_888 [86]
4 years ago
8

Please help me with this! if you know the answer, would you please explain it!

Mathematics
2 answers:
tia_tia [17]4 years ago
6 0

Answer:

A

Step-by-step explanation:

175/7=25

11*25=275

14*25=350

9*25=225

12*25=300

They are all true on A

Lynna [10]4 years ago
4 0

Answer:

A

Step-by-step explanation:

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Analyze the diagram below and complete the instructions that follow. (7x - 3) (12x -7) Solve for x.
yarga [219]

Answer:

Step-by-step explanation:

(7x-3)(12x-7)

we are solving for x and we are multiplying.

we start with the x's 7x*12x=  84x

-3*-7=21

so now we have

84x+21=0

the 0 is a placer for answering the question

we minus 21 to both sides

84x=-21

now we divide

84/-21= -4

x=-4

6 0
2 years ago
Please help will mark brainliest. what number should i put in the box?
ExtremeBDS [4]

Answer:

Greater than/equal to 9

Step-by-step explanation:

-⅓m《-3

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6 0
3 years ago
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the area of a rectangle of a barn is 200 square feet. the length is 10 feet longer than width . find the length and width of the
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Length x Width = 200 ==> (Width+10)Width = 200

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8 0
4 years ago
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Stan wants to start an IRA that will have $250,000 in it when he retires in 25 years. How much should he invest semiannually in
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8 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

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3 years ago
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