Find the common difference for the given sequence. 1.05, 1.1, 1.15, 1.2, ... 0.005 0.05 0.5
2 answers:
Answer: 0.05
Step-by-step explanation:
In the given sequence, the first term = 1.05
The second term = 1.1
The difference between first and second term =
The third term = 1.15
The difference between second and third term =
The fourth term = 1.2
The difference between third and fourth term =
Hence, the common difference of the given sequence =0.05
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Answer:
Option D -0.67
Step-by-step explanation:
Given : Preference of Brand A =30% ⇒
Preference of Brand B =70% ⇒
Prefer Brand A and are Female = 20% ⇒
Prefer Brand B and are Female = 40% ⇒
To find : Selected consumer is female, given that the person prefers Brand A
Solution : Using Bayes' theorem, which state that
where, P(A) and P(B) are probabilities of observing A and B.
P(B/A)= is a conditional probability where event B occur and A is true
P(A/B)= also a conditional probability where event A occur and B is true.
Now, applying Bayes' theorem,
Therefore, Option D is correct probability that a randomly selected consumer is female, given that the person prefers Brand A -0.67