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mr Goodwill [35]
2 years ago
10

Multiply the polynomial 2x(x−3) A)2x^2-6x B)2x-6 C)x^2-6

Mathematics
1 answer:
dlinn [17]2 years ago
6 0
Multiply 2x by each term in the parentheses:

2x(x - 3)
2x^2 - 6x

Answer:
2x^2 - 6x
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Which of the following is a quadratic function? <br><br> in photo..
Kaylis [27]

Answer:

f(x)=-3x^2

Step-by-step explanation:

A quadratic function is a function in which its degree (Highest power of the variable) is 2.

f(x)=-3x^2 is the function that has a degree of 2.

8 0
3 years ago
How to solve the question
Pani-rosa [81]
It should be 90cm
So it says 20cm multiply that by2 which is 40
Then add all the 10.
That is it!
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3 years ago
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Hayden has 6 rolls of dimes there are 50 dimes in each roll. How many dimes does he have altogether
DerKrebs [107]
This is pretty simple. :) Since you have 6 rolls of dimes with 50 dimes in each, you would just do 6*50 which equals 300. So Hayden has 300 dimes altogether. Hope this helps! :)
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3 years ago
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What is the longest line segment that can be drawn in a right rectangular prism that is 14 cm long 11 cm wide and 7 cm tall
weqwewe [10]

Answer:

The longest segment is approximately 19.13cm

Step-by-step explanation:

Given

l = 14cm

w = 11cm

h = 7cm

Required

The length of the longest segment (d)

This is calculated using:

d = \sqrt{l^2 +w^2 + h^2

So, we have:

d = \sqrt{14^2 +11^2 +7^2

Using a calculator, the equation becomes

d = \sqrt{366

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4 0
2 years ago
Find the equation of the parabola with focus at (3,3) and a directrix of y=1
vodomira [7]

Answer:

−4y

Step-by-step explanation:

Since the directrix is vertical, use the equation of a parabola that opens up or down.

(x−h)2=4p(y−k)

Find the vertex.

The vertex (h, k) is halfway between the directrix and focus. Find the y coordinate of the vertex using the formula y = y coordinate of focus + directrix 2. The x coordinate will be the same as the x coordinate of the focus.

(3,−1+1

    ___            

      2)

Simplify the vertex.

Add − 1 and 1. (3,0/2) Divide 0 by 2. (3,0).

Find the distance from the focus to the vertex.

The distance from the focus to the vertex and from the vertex to the directrix is | p |. Subtract the y coordinate of the vertex from the y coordinate of the focus to find p. p = − 1 − 0 Subtract 0 from − 1 . p = − 1.

Substitute in the known values for the variables into the equation ( x − h ) 2 = 4 p (y − k). (x − 3) 2 = 4 (− 1) (y − 0).

Simplify.

(x − 3) 2= −4y

= −4y

3 0
2 years ago
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