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artcher [175]
3 years ago
10

Which type of reaction does Sn2+ → Sn4+ represent?

Chemistry
1 answer:
bazaltina [42]3 years ago
3 0

As Sn undergoes removal of 4 electrons in this reaction, it is termed as oxidation reaction.

Explanation:

Chemical reactions can be further classified as oxidation and reduction reaction. As chemical reactions consists of transfer of electrons from one element to another, it leads to formation of oxidation and reduction reaction. It is known that if an element releases electrons to attain stable state, then that element is said to undergo oxidation reaction. Similarly, if an element accepts electrons to attain stable state , then it is termed as reduction reaction.

In the present case, the reactant side contains Sn element in 2+ ionized state or oxidized state as 2 electrons are already removed in this state. And in the product side, the oxidation number increased to +4 . This means more 2 electrons are released from Sn in the product side. So as Sn undergoes removal of 4 electrons in this reaction, it is termed as oxidation reaction.

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When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq).

How many moles of this process?

Relative atomic mass from a modern periodic table:

  • K: 39.098;
  • N: 14.007;
  • O: 15.999.

Molar mass of \text{KNO}_3:

M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of the process = Number of moles of \text{KNO}_3 dissolved:

\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}.

What's the enthalpy change of this process?

Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ} for 0.212162\;\text{mol}. By convention, the enthalpy change \Delta H measures the energy change for each mole of a process.

\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

4 0
3 years ago
In the ground-state electron configuration of fe3+, how many unpaired electrons are present? express your answer numerically as
Virty [35]
Answer:
            Iron has 5 unpaired electrons in Fe⁺³ state.

Explanation:

Iron having atomic number 26 has following electronic configuration in neutral state.

                             Fe =  1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d⁶

When Iron looses three electrons it attains +3 charge with following electronic configuration.

                             Fe⁺³ =  1s², 2s², 2p⁶, 3s², 3p⁶, 3d⁵

The five electrons in d-orbital exist in unpaired form as,

                          3(dz)¹, 3d(xz)¹, 3d(yz)¹, 3d(xy)¹, 3(dx²-y²)¹


3 0
3 years ago
What are 10 facts about light?
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Answer:

1. light is made up of energy

2. light travels in a straight line

3. the speed of light is exactly 299 792 km per second

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8. we can use light as tweezers

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Look at the diagram below , which shows gas particles in a container. If the piston was lowered, so that the size of the contain
raketka [301]

The pressure of the gas is expected to increase in accordance to Boyle's law.

<h3>What is Boyle's law?</h3>

Boyle's law states that, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.

By implication, when the piston is lowered and the volume of the gas is decreased, the pressure of the gas is expected to increase in accordance to Boyle's law.

Learn more about Boyle's law: brainly.com/question/1437490

3 0
2 years ago
A student mixes 20.0gof white KCl crystals with distilled water in a beaker. After the mixture was stirred, no crystals are visi
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Answer:d

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