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Strike441 [17]
2 years ago
15

Look at the diagram below , which shows gas particles in a container. If the piston was lowered, so that the size of the contain

er decreases, what would happen to the pressure? Explain your reasoning. In your explanation, include which gas law (Boyle's law, Charles' law, or Gay-Lussac's law) this involves.

Chemistry
1 answer:
raketka [301]2 years ago
3 0

The pressure of the gas is expected to increase in accordance to Boyle's law.

<h3>What is Boyle's law?</h3>

Boyle's law states that, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.

By implication, when the piston is lowered and the volume of the gas is decreased, the pressure of the gas is expected to increase in accordance to Boyle's law.

Learn more about Boyle's law: brainly.com/question/1437490

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If a reaction is reversible what are the relative amounts of reactant and product
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3 0
3 years ago
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Combustion analysis of 0.300 g of an unknown compound containing carbon, hydrogen, and oxygen produced 0.5213 g of co2 and 0.283
Lyrx [107]
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
                                        = 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
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- the mass of O = the total mass - the mass of C atom - the mass of H atom
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Convert the mass to mole by divided by molar mass
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6 0
3 years ago
You react 2.33 g of iron (III) chloride with 50.0 mL of 0.500 M solution of sodium phosphate to
nikklg [1K]

Answer:

2.33g of iron (iii) chloride

50.0 mL of 5.00 M of sodium phosphate

FeCl3 + Na3PO4 > Fe(PO4) + 3NaCl

mol = conc × vol = 0.5 × 50/1000 = 0.025 mol Na3PO4

from the equation:

1 mol of Na3PO4 reacts with 1 mol FeCl3 = 3 mol of NaCl

0.025 mol = x

x = 0.0025 × 3 = 0.075 mol NaCl

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i guessed all of this so i dont know i it is correct

3 0
2 years ago
λmax for the π → π* transition in ethylene is 170 nm. Is the HOMO-LUMO energy difference in ethylene greater than or less than t
-Dominant- [34]

Answer:

the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

Explanation:

The λmax is the wavelength of maximum absorption. We could use it to calculate the HOMO-LUMO energy difference as follows:

For ethylene

E= hc/λ= 6.63×10^-34×3×10^8/170×10^-9= 1.17×10^-18J

For cis,trans−1,3−cyclooctadiene

E= hc/λ=6.63×10^-34×3×10^8/230×10^-9=8.6×10^-19J

Therefore, the HOMO-LUMO energy difference in ethylene is greater than that of cis,trans−1,3−cyclooctadiene

8 0
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Underperform in extreme temperatures. ...

Expensive casing. ...

Expensive to transport.

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