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Strike441 [17]
2 years ago
15

Look at the diagram below , which shows gas particles in a container. If the piston was lowered, so that the size of the contain

er decreases, what would happen to the pressure? Explain your reasoning. In your explanation, include which gas law (Boyle's law, Charles' law, or Gay-Lussac's law) this involves.

Chemistry
1 answer:
raketka [301]2 years ago
3 0

The pressure of the gas is expected to increase in accordance to Boyle's law.

<h3>What is Boyle's law?</h3>

Boyle's law states that, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.

By implication, when the piston is lowered and the volume of the gas is decreased, the pressure of the gas is expected to increase in accordance to Boyle's law.

Learn more about Boyle's law: brainly.com/question/1437490

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A 500. mL gas sample is collected over water at a pressure of 740 mmHg and 25.0 °C. What is the volume of the dry gas at STP?
Lera25 [3.4K]

Answer:

Volume of dry gas at STP = 0.432 liters or 432 ml

Explanation:

Given:

Pressure (P) = 740 mmHg - 24 mmHg = 716 mmHg

Temperature (t) = 25 degrees C + 273 K = 298 K

500 ml = 0.5 l

Find:

Volume of dry gas at STP

Computation:

[P1][V1] / T1 = [P2][V2] / T2

[716][0.5] / 298 K = [760][ x Liters] / 273 K

x = 0.432 Liters

Volume of dry gas at STP = 0.432 liters or 432 ml

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3 years ago
One way to determine the degree of saturation of a solid-liquid solution is to drop a crystal of the solute into the solution.
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The answer is D: Saturated.

A saturated solution is one in which the exact maximum amount of solute has been dissolved.  So, new solute will not dissolve in the solution.  In contrast, an unsaturated solution can hold more solute, so if that option were correct, the crystal would have dissolved.

The other two terms are a bit more complicated.  A supersaturated solution is one holding an amount of solute above the sustainable limit.  Because of that, when more solute is added, the solution will immediately adjust, and some solute will come out of solution in a precipitate.  Because the crystal isn't growing, we can eliminate this option.

A concentrated solution is one holding a relatively large amount of solute.  However, you can have concentrated solutions that are saturated and unconcentrated (the word for this is dilute) solutions that aren't saturated.  Therefore, we can say that because the crystal doesn't dissolve, this solution is saturated, but we can't say with certainty that it is concentrated.

Because the first three options are invalid, as described above, while the scenario does describe a saturated solution, D is the correct answer.

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