Answer:
An emulsion is formed.
Explanation:
An association (emulsion) of two liquids is formed, in this case oil and vinegar, which when stirred, said mixture will separate.
The correct answer for the question that is being presented above is this one: "<span>0.3."
Here it is how to solve.
M</span><span>olecular mass of Ar = 40
</span><span>Molecular mass of Ne = 20
</span><span>Number of moles of Ar = 9.59/40 = 0.239
</span><span>Number of moles of Ne = 11.12/20= 0.556
</span><span>Mole fraction of argon = 0.239/ ( 0.239 + 0.556) = 0.3</span><span>
</span>
The correct answer is option b, that is, triggered by changes in the weather.
Hibernation refers to a state of lower metabolism and inactivity usually witnessed in endotherms. This condition is featured by a slow heart rate, slow breathing, low metabolic rate, and low body temperature. It assists the majority of the endotherms to thrive in the cold seasons. For example, hibernation of a bear in winters. Therefore, weather change can stimulate hibernation.
The heat of the reaction, in kJ, when 4.18 g of the hydrocarbon are combusted 775.70 kJ.
The heat energy is given as :
q = m c ΔT + Ccal ΔT
q = ( 974 g× 4.184 ×6.9) + 624 ×6.9
q = 32424.59 J
moles of hydrocarbon = 0.0418 mol
heat of combustion = 32424.59 J / 0.0418 mol
= 775707.89 J
= 775.70 kJ
Thus, A 4.18 g sample of a hydrocarbon is combusted in a bomb calorimeter that contains 974 g of water. the temperature of the water increases by 6.9 °C when the hydrocarbon is combusted. the calorimeter constant for the calorimeter was determined to be 624 J/°C. what is the heat of the reaction is 775.70 kJ.
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There are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2. Details about formula units can be found below.
<h3>What is a formula unit?</h3>
Formula unit refers to the empirical formula of an ionic compound for use in stoichiometric calculations.
According to this question, there are 111g of CaCl2. The formula units can be calculated by multiplying the number of moles by Avogadro's number.
no of moles in CaCl2 = 111g ÷ 111g/mol = 1mol
Formula units of CaCl2 = 1mol × 6.02 × 10²³ = 6.02 × 10²³ formula units.
Therefore, there are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2.
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