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Strike441 [17]
2 years ago
15

Look at the diagram below , which shows gas particles in a container. If the piston was lowered, so that the size of the contain

er decreases, what would happen to the pressure? Explain your reasoning. In your explanation, include which gas law (Boyle's law, Charles' law, or Gay-Lussac's law) this involves.

Chemistry
1 answer:
raketka [301]2 years ago
3 0

The pressure of the gas is expected to increase in accordance to Boyle's law.

<h3>What is Boyle's law?</h3>

Boyle's law states that, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.

By implication, when the piston is lowered and the volume of the gas is decreased, the pressure of the gas is expected to increase in accordance to Boyle's law.

Learn more about Boyle's law: brainly.com/question/1437490

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A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
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Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

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m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

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Explanation:

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