Answer:
0.42 M
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
The mole ratio of acid, HCl (nₐ) = 1
The mole ratio of base, NaOH (n₆) = 1
Finally, we shall determine the molarity of the base, NaOH. This can be obtained as follow:
Volume of acid, HCl (Vₐ) = 25 mL
Molarity of acid, HCl (Mₐ) = 0.25 M
Volume of base, NaOH (V₆) = 15 mL
Molarity of base, NaOH (M₆) =?
MₐVₐ / M₆V₆ = nₐ/n₆
0.25 × 25 / M₆ × 15 = 1
6.25 / M₆ × 15 = 1
Cross multiply
6.25 = M₆ × 15
Divide both side by 15
M₆ = 6.25 / 15
M₆ = 0.42 M
Therefore, the molarity of the base, NaOH is 0.42 M
