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murzikaleks [220]
3 years ago
5

In the first recrystallization, after the solid has been dissolved in warm acetone, the solution is allowed to cool slowly to ro

om temperature. In an older procedure the warm solution was placed directly into an ice bath. How does this older procedure differ from a normal recrystallization and what might be the consequences
Chemistry
1 answer:
zvonat [6]3 years ago
6 0

Answer:

See explanation below.

Explanation:

In the older procedure, the solution is cooled so quickly that the recrystallization can be less effective. By allowing the solution to cool slowly, the maximum amount of crystal is formed, and also the impurities are trapped, so the process is more controlled than by the older one.

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A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH
Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5    → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0
3 years ago
What does the δ– symbol mean on a water diagram?
Law Incorporation [45]

Answer:

a or

Explanation:

im guessing that it has to involve something with a negative

4 0
3 years ago
Read 2 more answers
Which functional group does the molecule below contain
DedPeter [7]

Answer:

All functional groups in organic chemistry

Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

Hope this helps Have a good day

7 0
3 years ago
Read 2 more answers
Helppp ! Please :’)
Over [174]

Answer:

\boxed{\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm}

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

\frac{1}{ \lambda}  = R_H {Z}^{2}  \big(\frac{1}{{n_f^2}}  - \frac{1}{{n_i^2}} \big)

Where,

  • λ is wavelength of photon
  • Rʜ is rydberg constant, the value of Rʜ is

109690 Cm-¹ in <em>Puri Sharma Pathania</em> standard book of physical chemistry &

109737 Cm-¹ according to <em>Wikipedia</em>

  • Z is the atomic number of atom, for hydrogen Z =1,

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{3^2}}  - \frac{1}{{5^2}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{9}}  - \frac{1}{{25}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{25 - 9}{25 \times 9}

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{16}{225}

\frac{1}{ \lambda}  =   7800.18 \: \: cm ^{ - 1}

\lambda = 1.282 \times  {10}^{ - 4} cm

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

\lambda \:  = 1.282 \times  {10}^{ - 4} \times  {10}^{7}

\lambda \:  = 1.282 \times  {10}^{ - 4 + 7}

\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm

\sf \small Thanks \:  for \:  joining \:  brainly  \: community!

4 0
2 years ago
The equilibrium constant for the following equation:
Mkey [24]

From the calculation, the partial pressure of Cl2 is 1.98 atm. Option B

<h3>What is the equilibrium constant?</h3>

The term equilibrium constant refers to the value that shows us the extent to which reactants are converted into products. We know that the equilibrium constant can only be obtained by the use of the equilibrium partial pressures of each of the species.

Thus we have;

K = p PCl3 . pCl2/pPCl5

p PCl3 = partial pressure of PCl3

pCl2 = partial pressure of Cl2

pPCl5 = partial pressure of PCl5

K = equilibrium constant

Substituting values;

1.05 =  0.463 *  pCl2/0.875

 pCl2 = 1.05  * 0.875/0.463

pCl2 = 1.98 atm

Learn more about equilibrium constant:brainly.com/question/10038290

#SPJ1

4 0
2 years ago
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