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Vesnalui [34]
3 years ago
6

What is a 2 digit number between 20 and 99

Mathematics
2 answers:
Mazyrski [523]3 years ago
5 0

Any number between 20 and 99

PilotLPTM [1.2K]3 years ago
4 0
Any number from 21-98 is between 20 and 99.
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Need answer ASAP:
stealth61 [152]

Answer:

Step-by-step explanation:first you multiply 0.76 by 14then multiply 0.68 by 8 then multiply 6.71 by 4. After you get your answer for each one you add them by the cost of each one

7 0
3 years ago
2. Round off the decimal: (a) 3.153 to the nearest tenths (b) 10.126 to the nearest hundredths (c) 5.0014 to the nearest thousan
Monica [59]

Answer:

(a)3.15,(b)10.1,(c)5.0,(d)6.00,(e)21.8,(f)3.1

5 0
3 years ago
The average score of all golfers for a particular course has a mean of 71 and a standard deviation of 3. Suppose 36 golfers play
Zielflug [23.3K]

Answer:

.0228

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 71, \sigma = 3, n = 36, s = \frac{3}{\sqrt{36}} = 0.5

Find the probability that the average score of the 36 golfers exceeded 72.

This is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{72 - 71}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

7 0
3 years ago
I need help if help 5 pt
german

3 3/4 = 15/4

15/4 * 1/2 = 15/8 = 1 7/8

answer: he put 1 7/8 into the riding lawn mower

5 0
3 years ago
The coordinate of the midpoint of segment AB is (-3, 2). Find the coordinate of A if the coordinate of B is (0, 2).
Anastaziya [24]
The answer is (-6,2). I hope this helped you!
8 0
4 years ago
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