Answer:
39.57 °C
Explanation:
Applying,
Heat gain = Heat lost.
cm'(t₃-t₁) = cm(t₂-t₃)................. Equation 1
Where c = specific heat capacity of water, m = mass of the hotter water, m' = mass of the colder water, t₁ = initial temperature of the colder water, t₂ = initial temperature of the hotter water, t₃ = Final Temperature.
Equation 1 above can futher be simplified to
m'(t₃-t₁) = m(t₂-t₃)................. Equation 2
From the question,
Given: m' = 155 g, m' = 75 g, t₁ = 20 °C, t₂ = 80 °C
Substitute these values into equation 2
155(t₃-20) = 75(80-t₃)
Solve for t₃
155t₃- 3100 = 6000-75t₃
155t₃+75t₃ = 6000+3100
230t₃ = 9100
t₃ = 9100/230
t₃ = 39.57 °C
Answer:
The answer is
<h2>150 mL</h2>
Explanation:
To convert the volume from cm³ to mL we use the conversion
1 cm³ = 1 mL
So from the question
if 1 cm³ = 1 mL
Then 150 cm³ = 150 mL
Hope this helps you
The ground state electron configuration of ground state gaseous neutral tin is 4d to the power of 10. 5s to the power of 2. And 5p to the power of 2. And the term symbol is 3P0
Answer:
the final temperature is T=305.63 K
Explanation:
using the Stephan-Boltzmann equation for black bodies
q = σ*(T⁴-T₀⁴)
where
q= heat flux = 155 W/m²+150 W/m² = 255 W/m²
σ= Stephan-Boltzmann constant = 5.67*10⁻⁸ W/m²K⁴
T= absolute temperature
T₀= absolute initial temperature = 255 K
solving for T
q = σ*(T⁴-T₀⁴)
T = (q/σ + T₀⁴)^(1/4)
replacing values
T = (q/σ + T₀⁴)^(1/4) = (255 W/m²/(5.67*10⁻⁸ W/m²K⁴) + (255 K)⁴)^(1/4) = 305.63 K
T=305.63 K
thus the final temperature is T=305.63 K
