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katovenus [111]
3 years ago
10

A gas has a volume of 150 cm3. Convert this volume into mL

Chemistry
1 answer:
kompoz [17]3 years ago
3 0

Answer:

The answer is

<h2>150 mL</h2>

Explanation:

To convert the volume from cm³ to mL we use the conversion

1 cm³ = 1 mL

So from the question

if 1 cm³ = 1 mL

Then 150 cm³ = 150 mL

Hope this helps you

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Please help! It’s due today. I’ll give brainliest
MArishka [77]

Answer:

look at it is the correct answer because if a new gas has formed bubbles will how or change of colour so look at it

Explanation:

5 0
3 years ago
Read 2 more answers
Hydrogen is diffusing through solid nickel. At a temperature of 358 K, the diffusivity is 1.16 x 10-8 cm2/s. At a temperature of
Lelu [443]

Answer:

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

Explanation:

Consider the following equations:

lnD_{1} =lnD_{o} -\frac{Q_{d} }{R*T_{1} }

lnD_{2} =lnD_{o} -\frac{Q_{d} }{R*T_{2} }

Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:

Q_{d}=-R*\frac{lnD_{1} -lnD_{2} }{\frac{1}{T_{1} }-\frac{1}{T_{2} }  }

where:

Q_d is the activation energy

D_1 is the diffusivity at T_1

D_2 is the diffusivity at T_2

Q_{d}=-8.31*\frac{ln1.16*10^-12 -ln1.05*10^-11 }{\frac{1}{358 }-\frac{1}{438 }  }

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

3 0
4 years ago
Determine the volume of occupied by 4 moles of carbon dioxide gas at
valentina_108 [34]

Answer:

Vol of 4 moles CO₂(g) at STP = 89.6 Liters

Explanation:

STP

P = 1 Atm

V =

T = 0°C = 273 K

n = 4 moles

R = 0.08206 L·Atm/mol·K

Using Ideal Gas Law PV = nRT => V = nRT/P

V = (4 moles)(0.08206 L·Atm/mol·K)(273 K)/(1 Atm) = 89.6 Liters

5 0
3 years ago
A quantity of 85.0 mL of 0.900 M HCl is mixed with 85.0 mL of 0.900 M KOH in a constantpressure calorimeter that has a heat capa
bogdanovich [222]

Explanation:

The given data is as follows.

         V_{1} = 85.0 ml,        M_{1} = 0.9 M

         V_{2} = 85.0 ml,        M_{1} = 0.9 M

Hence, number of moles of HCl and KOH will be the same because both the solutions have same volume and molarity.

So,     No. of moles = Molarity × Volume

                                = 0.9 M \times 0.085 L        (as 1 L = 1000 ml so, 85 ml = 0.085 L)

                                = 0.076 mol

As 1 mole gives 56.2 kJ/mol of heat of neutralization. Hence, calculate the heat of neutralization given by 0.076 moles as follows.

              56.2 kJ/mol \times 0.076 mol

                    = 4.271 kJ

or,                 = 4271 J     (as 1 kJ = 1000 J)

Therefore,    heat released = - heat of gained by calorimeter

Since, it is given that density of the solution is similar to the density of water which is 1 g/ml.

Hence,     mass of HCl = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Similarly,    mass of KOH = = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Hence, total mass of the solution = 85 g + 85 g

                                                        = 170 g

Also,                   q = mC \Delta T

                     4271 J = 170 g \times 325 J/^{o}C \times (T_{f} - 18.24)^{o}C    

                     0.0773 = T_{f} - 18.24

                    T_{f} = 18.317^{o}C  

Thus, we can conclude that final temperature of the mixed solution is 18.317^{o}C.

6 0
3 years ago
H2+O=???????????????????
Luden [163]

Answer:

H₂O

Explanation:

Two molecules of Hydrogen and one molecules of Oxygen, when mixed, create H₂O, or water. There is no scientific name for H₂O due to it's common name. It is just refereed to as "water" or H₂O.

6 0
3 years ago
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