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Sladkaya [172]
4 years ago
7

What is Electron configuration for a tin atom in the excited state and why

Chemistry
1 answer:
galina1969 [7]4 years ago
5 0
The ground state electron configuration of ground state gaseous neutral tin is 4d to the power of 10. 5s to the power of 2. And 5p to the power of 2. And the term symbol is 3P0
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Determine where to dispose of each type of waste.
sattari [20]

Syringe tips and titrant solution in a container,  unused solid reagent in the manufacturer's container and  broken flask in the cardboard box.

Syringe tips are dispose into the disposal containers present in the lab or hospitals.  Unused solid reagent is dispose in the manufacturer's container and then label the container with a hazardous waste tag so that people can't use it and stay away from it.  

Broken flask is dispose in the cardboard box or a container.  Titrant solution can also be dispose by placing in a container which is leak proof and closed the opening tightly so that it can't pollute and damaged the outside world.

Learn more: brainly.com/question/24610949

4 0
3 years ago
Read 2 more answers
Please tell me if i did it right. did i put the right electric charge
Elina [12.6K]

Answer:

its good but your answer

6 0
3 years ago
Convert 296 degrees Celsius to Kelvin.<br> A. 23 K<br> B. 552 K<br> C. 569 K<br> D. 550 K
katovenus [111]

Answer:

option c) 552 K is correct

Explanation:

we know that

0° C +273= 273 K

so

296° C+273=569 K

7 0
2 years ago
Read 2 more answers
In the laboratory a general chemistry student finds that when 2.84 g of KClO4(s) are dissolved in 107.70 g of water, the tempera
vredina [299]

Answer : The enthalpy change of dissolution of KClO_4 is 54.3 kJ/mole

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 1.55J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 107.70 g

\Delta T = change in temperature = T_2-T_1=(22.80-20.34)=2.46^oC

Now put all the given values in the above formula, we get:

q=[(1.55J/^oC\times 2.46^oC)+(107.70g\times 4.184J/g^oC\times 2.46^oC)]

q=1112.3J=1.1123kJ

Now we have to calculate the enthalpy change of dissolution of KClO_4

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 1.1123 kJ

m = mass of KClO_4 = 2.84 g

Molar mass of KClO_4 = 138.55 g/mol

\text{Moles of }KClO_4=\frac{\text{Mass of }KClO_4}{\text{Molar mass of }KClO_4}=\frac{2.84g}{138.55g/mole}=0.0205mole

\Delta H=\frac{1.1123kJ}{0.0205mole}=54.3kJ/mole

Therefore, the enthalpy change of dissolution of KClO_4 is 54.3 kJ/mole

5 0
4 years ago
Why would an atom emit particles or waves from its nucleus?
Neko [114]

Answer:

It’s A non of these

Explanation:

5 0
3 years ago
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