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Usimov [2.4K]
3 years ago
10

The growing of plants, burning of wood, and decomposition of living matter demonstrate how carbon can be in the _______ at the s

ame time. a. atmosphere and biosphere b. biosphere and geosphere c. geosphere and atmosphere d. atmosphere, biosphere, and geosphere
Chemistry
2 answers:
JulijaS [17]3 years ago
8 0

Answer:

d. atmosphere, biosphere, and geosphere

Explanation:

Carbon is one of the most common elements on the planet, with large reservoirs in the biosphere, atmosphere, geosphere and hydrosphere in the form of carbohydrates, proteins, nucleic acids, carbon dioxide and calcium carbonate. Events such as plant cultivation, wood burning and decomposition of living matter prove that carbon is in the above mentioned environments simultaneously as these events are the result of adding to the carbon removal from these environments.

With its strong influence on the interaction between molecules, the carbon cycle is a fundamental process for maintaining life on earth. Responsible for photosynthesis and keeping the planet warm through the greenhouse effect, without it we would not be here.

Fittoniya [83]3 years ago
3 0
I think the answer is in the ground at the same time            

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after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2
Alexxandr [17]
Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
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22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3

2) 725 ml = 0.725 L




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3 years ago
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Read 2 more answers
Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you
Alja [10]

<u>Answer:</u> The molality of the solution is 0.11 m

<u>Explanation:</u>

We are given:

Mole fraction of methanol = 0.135

This means that 0.135 moles of methanol is present in 1 mole of a solution

Moles of ethanol = 1 - 0.135 = 0.865 moles

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of ethanol = 0.865 moles

Molar mass of ethanol = 46 g/mol

0.865mol=\frac{\text{Mass of ethanol}}{46g/mol}\\\\\text{Mass of ethanol}=(0.865mol\times 46g/mol}=39.79g

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (methanol) = 0.135 g

M_{solute} = Molar mass of solute (methanol) = 32 g/mol

W_{solvent} = Mass of solvent (ethanol) = 39.79 g

Putting values in above equation, we get:

\text{Molality of methanol}=\frac{0.135\times 1000}{32\times 39.79}\\\\\text{Molality of methanol}=0.106m\approx 0.11m

Hence, the molality of the solution is 0.11 m

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3 years ago
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Answer:

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Explanation:

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