Answer:
No, the given polynomial is not prime.
Step-by-step explanation:
Given: a polynomial 
To check: whether the given polynomial is prime or not.
Solution:
A prime polynomial is a polynomial that cannot be factored into polynomials of lower degree and has integers as coefficients.
In the given polynomial, coefficients are integers.
Also, the polynomial cannot be factored further into polynomials of lower degree.
So, the given polynomial is not prime.
Answer:
y = 13
Step-by-step explanation:
Step 1: Distribute
3/2y - 3/2 = y + 5
Step 2: Subtract <em>y</em> on both sides
1/2y - 3/2 = 5
Step 3: add 3/2 on both sides
1/2y = 13/2
Step 4: Divide both sides by 1/2
y = 13
x is greater than or equal to 0
x is less than or equal to 1
put the equation in desmos to graph the inequality
Answer: x = 2
Step-by-step explanation:
The rule for reflecting over x = 2 is that y remains the same and you add how many units x = 2 is from the point.
x = 2 is has the coordinate of x = 2 and y = the y coordinate of the point.
A (-1, 1) Since the y coordinate of (-1, 1) is 1, x = 2 - (2, 1)
Add 3 units to 2, the x coordinate since -1, 1 is 3 units from 2, 1
2,1 --> 5, 1
I really didn't know how to explain but Im 100% sure Im right and I hoped this helped somehow.
No, Tyson's final expression is not equivalent to the initial expression.
<h3>Fraction addition;</h3>
According to Tyson's evaluation after collecting like terms; we have;
- 1/5g +(-1g) + 1(3/10g) + (-1/10) + (-1/10)
open parenthesis
- 1/5g - 1g + 3/10g - 1/10 - 1/10
Upon addition of like terms; we have;
Hence, the correct expression is; (-1/2)g -1/5
Read more on fraction addition;
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