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gladu [14]
3 years ago
15

A student is working with three sealed containers filled with water. The first container is filled with ice. The second is fille

d with liquid water, and the third is filled with water vapor. Each container has a plunger on top. What will happen to the volumes of each container when the student presses the plungers
Engineering
1 answer:
Temka [501]3 years ago
6 0

Explanation:

The three containers each contains water in different states.

Solid state of matter is considered as not compressible because the molecules are already as closely packed as they can be.

The liquid sate of matter has a very minute to no compression ability at all as the molecules are relatively close to each other. Compression is difficult to achieve in the liquid state.

In the gaseous state of matter, the molecules have broken free of one another, and are fairly spaced one from another. This means that gases can be easily compressed.

Pressing down on the plunger, the container containing ice can't be compressed at all so it's volume stays the same.

For the container filled with water, only a minute compression can be achieved with great difficulty hence, the volume reduces by an insignificant amount.

For the container filled with vapour, compression can be easily achieved and the volume reduces significantly.

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3. What is a caliber (relate it to rockets)
Kamila [148]

Answer:

In this context a caliber is defined as the diameter of the body tube, and it is used to support the general rule of thumb that for a rocket of typical aspect ratio to be stable the CG should be one caliber ahead of CP.

Explanation:

6 0
3 years ago
The electricity generated by wind turbines annually in kilowatt-hours per year is given in a file. The amount of electricity is
Anika [276]

Answer:

Steps:

1. Create a text file that contains blade diameter (in feet), wind velocity (in mph) and the approximate electricity generated for the year

2.  load the data file for example, in matlab, use ('fileame.txt') to load the file

3. create variables from each column of your data

  for example, in matlab,  

     x=t{1}

     y=t{2}

4. plot the wind velocity and electricity generated.

   plot(x, y)

5. Label the individual axis and name the graph title.

    title('Graph of wind velocity vs approximate electricity generated for the year')

     xlabel('wind velocity')

     ylabel('approximate electricity generated for the year')

5 0
3 years ago
Read 2 more answers
Consider tests of an unswept wing that spans the wind tunnel and whose airfoil section is NACA 23012. Since the wing model spans
Dominik [7]

Answer:

Check the explanation

Explanation:

to know the lift per unit span (N/m) that is expected to be measured when the wing attack angle is 4°

as well as the corresponding section lift coefficient and die moment coefficient .

Kindly check the attached image below to see the step by step explanation to the above question.

3 0
3 years ago
A 36 ft simply supported beam is loaded with concentrated loads 16 ft inwards from each support. On the left side, the dead load
lana66690 [7]

Answer:

1st part: Section W18X76  is adequate

2nd part: Section W21X62 is adequate

Explanation:

See the attached file for the calculation

8 0
3 years ago
Q1. (20 marks) Entropy Analysis of the heat engine: consider a 35% efficient heat engine operating between a large, high- temper
Anvisha [2.4K]

The rate of gain for the high reservoir would be 780 kj/s.

A. η = 35%

\frac{w}{Q1} = \frac{35}{100}

W = 1.2*\frac{35}{100}*1000kj/s

W = 420 kj/s

Q2 = Q1-W

= 1200-420

= 780 kJ/S

<h3>What is the workdone by this engine?</h3>

B. W = 420 kj/s

= 420x1000 w

= 4.2x10⁵W

The work done is 4.2x10⁵W

c. 780/308 - 1200/1000

= 2.532 - 1.2

= 1.332kj

The total enthropy gain is 1.332kj

D. Q1 = 1200

T1 = 1000

\frac{1200}{1000} =\frac{Q2}{308} \\\\Q2 = 369.6 KJ

<h3>Cournot efficiency = W/Q1</h3>

= 1200 - 369.6/1200

= 69.2 percent

change in s is zero for the reversible heat engine.

Read more on enthropy here: brainly.com/question/6364271

6 0
3 years ago
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