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3 years ago

Saul is testing an installation and discovers a short circuit. What's causing this?

Engineering

1 answer:

sergey [27]3 years ago

6 0

A high voltage!! Hope this helps

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Piessunzed water (pin-10 bar, Tin= 1 10°C) enters the hottom of an L 12-m-long vertical tube of diameter D110 mm at a mass flow

Westkost [7]

Answer:

(1) $\Delta E_{tw}=4845.43 kW$

(2) $\Delta E_m=6.329 kW$

(3) $\Delta E_t= 4851.759 kW$

(4) $q= 4851.759 kW$

Explanation:

At the saturation temperature, water starts boiling, and before that heat is added at constant pressure as latent heat.

From the saturated water-pressure table, at the pressure $P=10$ bar, we have

The saturated temperature of the water, $T_{sw}=179.88^{\circ} C$

The specific volume of water, $v_{ws}=v_f=0.00127 m^3/kg$

Specific enthalpy of water, $h_{ws}=h_f=762.50 kJ/kg$

The given inlet temperature of the water, $T_i=110^{\circ}$ , so, latent heat added to the water to reach the saturation temperature is

$h_l=C_P(T_{sw}-T_i)$

$\Rightarrow h_l=4.187(179.88^{\circ} -110^{\circ}$

$\Rightarrow h_l=292.587 kJ/kg$

Now, specific enthalpy of the water at the inlet $=$ (specific enthalpy of the water at the saturation temperature) $-$ (Latent heat capacity).

$\Rightarrow h_i=h_{sw}-h_l$

$\Rightarrow h_i=762.50-292.587=469.912kJ/kg$

The specific volume of the water at intel is the same as the specific volume at the saturation temperature as volume remains unchanged on the addition of latent heat.

So, $v_i=v_{ws}=0.00127 m^3/kg$ .

The outlet temperature, $T_o=600^{\circ} C$ and pressure, $P_o=7$ bar. From the superheated water table, we have

The specific volume of water, $v_o=0.5738 m^3/kg$

The specific enthalpy of water, $h_{wo}=3700.9 kJ/kg$

The given mass flow rate, $\dot{m} =1.5 kg/s$ .

The inlet radius and outlet diameter are the same, i.e

$d_i=d_o=110 mm=0.11m$ .

So, Inlet and outlet areas, $A_i=A_f=9.5033\times 10^{-3} m^2$ .

Let the inlet and outlet velocities be $V_i$ and $V_o$ respectively.

For the given specific volume, $v$ , and mass flow rate, $\dot{m}$ , the velocity, $V$ , at any cross-section having an area $A$ is

$V=\frac{v\dot{m}}{A}$ .

So, the inlet velocity,

$V_i=\frac{v_i \dot{m}}{A_i}$

$\Rightarrow V_i=\frac{0.00127\times 1.5}{9.5033\times 10^{-3}}$

$\Rightarrow V_i=0.20 m/s$ .

Similarly, the outlet velocity,

$V_o=\frac{v_o \dot{m}}{A_o}$

$\Rightarrow V_o=\frac{0.5738\times 1.5}{9.5033\times 10^{-3}}$

$\Rightarrow V_0=90.57 m/s$ .

(1) The change in combined thermal energy and work flow $=$ Change in the thermal energy $+$ Change in the flow work

$\Delta E_{tw}= \dot{m}(u_f-u_i)+\dot{m} (P_fv_f-P_iv_i)$

$\Rightarrow \Delta E_{tw}=\dot{m}[(u_f+P_fv_f) - (u_i+P_iv_i)$

$\Rightarrow \Delta E_{tw}=\dot{m} (h_f-h_i)$

$\Rightarrow \Delta E_{tw}=1.5(3700,20-469.912)=4845.43 kW$

(2)The change in mechanical energy

$\Delta E_m=$ Change in kinetic energy + change in potential energy

$\Rightarrow \Delta E_m=\left(\frac 1 2 \dot{m} V_f^2-\frac 1 2 \dot{m} V_i^2\right)+(\dot{m} g z_f-\dot{m} g z_i)$

$\Rightarrow \Delta E_m=\frac 1 2 \dot{m}(V_f^2-V_i^2)+\dot{m} g (z_f-z_i)$

$\Rightarrow \Delta E_m=\frac 1 2\times 1.5((90.57)^2-(0.2)^2)+1.5 \times 9.81 \times12$

$\Rightarrow \Delta E_m=6328.74 J/s=6.329 kW$

(3) The change in the total energy of water,

$\Delta E_t=$ chnge in the thernal energy + change in the flow work + change in the mechanical energy

$\Rightarrow \Delta E_t=4845.43+6.329= 4851.759 kW$ [from part (1) and (2)]

(4) Now, as there is no work done by the water, so, the heat input only caused the change in the total energy.

Hence, the rate of heat transfer, $q= 4851.759 kW$ [from part (3).

7 0

3 years ago

Oliver is designing a new children's slide to increase speed at which a child can descend.His first design involved steel becaus

goldenfox [79]

Answer:

Steel can rusts easily in the presence of moisture and oxygen, and tarnishes as the rust progresses.

Explanation:

Steel is an alloy of carbon and iron. it is a very useful alloy that is found in almost any engineered piece. The problem with steel is that it is very susceptible to rust, and the cost of maintaining it in order to prevent rust is very high. Steel rusts in the presence of moisture and oxygen (rust is an oxidation-reduction process). Using it as a water slide exposes it constantly to moisture, and to prevent it from rusting in this case will involve a lot of maintenance cost, which is why steel is not advisable to be used in this case.

7 0

4 years ago

How can historical design elements be added to modern building plans?

satela [25.4K]

Answer:

is it to late now

Explanation:

5 0

3 years ago

Read 2 more answers

The lid on a pressure vessel is held down with 10 bolts that pass through the lid and a flange on the pressure vessel (similar t

Volgvan

Answer:

25120 N

Explanation:

The external load acting on each bolted joint

= P x A / N

= (8 x 10⁶) (31.4 x 10³ x 10⁻⁶) / 10

= 25120 N

4 0

4 years ago

Write down the three formula to find the three types of slope of curve Q with respect to L.

harina [27]

The three formula for finding out the 3 types of the slope of curve Q with respect to L should be explained below.

<h3>Three formulas:</h3>

1. Slope intercept form where the formula is y = mx + b

Here

y = variable

m = slope of line

x = variable

b = y intercept

2. Point slope form where the formula is y - y1 = m(x - x1)

Here

y = variable

y1 = y coordinate at the first point on line

m = the slope

x = variable

x1 = x coordinate at the first point on line

3. Standard slope form where the formula is ax + by = c

Here

a = x coefficent

b & c = constant term

learn more about formula here: brainly.com/question/24454271

7 0

2 years ago

Read 2 more answers