Answer:
No
Explanation:
The "need" to build a roller coaster would not be considered an engineering design problem. This would be more of a management/accounting problem because they are the ones that analyze numbers and decide what the amusement park would need in order to maintain/increase profitability by attracting more customers. Therefore, if they "need" a new roller coaster to do so then it becomes their problem. For it to be an engineering design problem the statement should be "the need to design a roller coaster with certain specifics" or something along those lines.
Answer:
<em>v</em><em> </em>= T/(2R)
Explanation:
Given
R = radius
T = strength
From Biot - Savart Law
d<em>v</em> = (T/4π)* (d<em>l</em> x <em>r</em>)/r³
Velocity induced at center
<em>v </em>= ∫ (T/4π)* (d<em>l</em> x <em>r</em>)/r³
⇒ <em>v </em>= ∫ (T/4π)* (d<em>l</em> x <em>R</em>)/R³ (<em>k</em>) <em>k</em><em>:</em> unit vector perpendicular to plane of loop
⇒ <em>v </em>= (T/4π)(1/R²) ∫ dl
If l ∈ (0, 2πR)
⇒ <em>v </em>= (T/4π)(1/R²)(2πR) (<em>k</em>) ⇒ <em>v </em>= T/(2R) (<em>k</em>)
Answer:
# Program is written in python
# 22.1 Using the count method, find the number of occurrences of the character 's' in the string 'mississippi'.
# initializing string
Stringtocheck = "mississippi"
# using count() to get count of s
counter = Stringtocheck.count('s')
# printing result
print ("Count of s is : " + str(counter))
# 2.2 In the string 'mississippi', replace all occurrences of the substring 'iss' with 'ox
# Here, we'll make use of replace() method
# Prints the string by replacing iss by ox
print(Stringtocheck.replace("iss", "ox"))
#2.3 Find the index of the first occurrence of 'p' in 'mississippi'
# declare substring
substring = 'p'
# Find index
index = Stringtocheck.find(substring)
# Print index
print(index)
# End of program
Answer:
Plastic deformation, irreversible or permanent. Deformation mode in which the material does not return to its original shape after removing the applied load. This happens because, in plastic deformation, the material undergoes irreversible thermodynamic changes by acquiring greater elastic potential energy.
Elastic deformation, reversible or non-permanent. the body regains its original shape by removing the force that causes the deformation. In this type of deformation, the solid, by varying its tension state and increasing its internal energy in the form of elastic potential energy, only goes through reversible thermodynamic changes.
Answer:
- public class Main {
- public static void main(String[] args) {
- String testString = "abscacd";
-
- String evenStr = "";
- String oddStr = "";
-
- for(int i=testString.length() - 1; i >= 0; i--){
-
- if(i % 2 == 0){
- evenStr += testString.charAt(i);
- }
- else{
- oddStr += testString.charAt(i);
- }
- }
-
- System.out.println(evenStr + oddStr);
- }
- }
Explanation:
Firstly, let declare a variable testString to hold an input string "abscacd" (Line 1).
Next create another two String variable, evenStr and oddStr and initialize them with empty string (Line 5-6). These two variables will be used to hold the string at even index and odd index, respectively.
Next, we create a for loop that traverse the characters of the input string from the back by setting initial position index i to testString.length() - 1 (Line 8). Within the for-loop, create if and else block to check if the current index, i is divisible by 2, (i % 2 == 0), use the current i to get the character of the testString and join it with evenStr. Otherwise, join it with oddStr (Line 10 -14).
At last, we print the concatenated evenStr and oddStr (Line 18).
