The Lagrangian for this function and the given constraints is

which has partial derivatives (set equal to 0) satisfying

This is a fairly standard linear system. Solving yields Lagrange multipliers of

and

, and at the same time we find only one critical point at

.
Check the Hessian for

, given by


is positive definite, since

for any vector

, which means

attains a minimum value of

at

. There is no maximum over the given constraints.
Answer:
8x-18
Step-by-step explanation:
ggv dcbbccc. bvvccv. vccbv. vvvvv
Answer:
"Variable interval" is the right solution.
Step-by-step explanation:
- A variable-interval timetable seems to be a fiber-reinforced routine where another sensitivity or reaction would be commended because an unanticipated or unstable transaction has taken place, which would be the exact reverse of either a fixed-interval routine.
- The whole such schedule results in a slow or predictable, fairly constant targeted respondents.