current . . . flow of electric charges
voltage . . . stored potential energy at the source of a circuit
resistance . . . opposition to the flow of electric current
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
Answer:
The speed of elevator fast and slows down shows through the diagram.
Explanation:
Given that,
Amanda has just entered an elevator. The elevator rises and stops at the third floor.
Let us consider the elevator at rest then the speed will be zero.
When elevator start from rest then the speed increases with constant acceleration and near the third floor it slow down with constant deceleration and finally becomes at rest at third floor.
We need to draw the diagram distance and time
Using given data,
First, the displacement A to B will be increases fastly and B to C the displacement increases slowly slowly.
Hence, The speed of elevator fast and slows down shows through the diagram.
Answer:
Explanation:
a ) Refractive index (μ ) = Sin i / Sin r
i is angle of incidence = 30.2 and r is angle of refraction = 18.5 degree
μ = Sin 30.2 / sin 18.5 = 0.5030 / .3173 = 1.585.
b ) Wave length in a medium = wavelength in air / refractive index
= 632.8 / 1.585 = 399.24 nm.
c ) frequency in solution = frequency in vacuum
=
= 47 x 10¹³ Hz
d ) Speed in the solution = Speed in vacuum / Refractive index
=
= 1.893 x 10⁸ ms⁻¹.
First reason is safety, of course.
Second reason, the hot object radiates heat in the form of convection current which will heat the air around it.
This current can cause instabilities in measurements especially when using sensitive digital scales.
Answer:
The normal force the ground exerts on the block, F = -300 N
Explanation:
Given data,
The block pulled up with a tension force, T = 100 N
The weight of the block, W = 300 N
The weight of the block is due to the force of attraction of gravitation.
The surface exerts a force that is equal and opposite to the force acting on the block due to gravitation.
The weight of the block,
W = mg
300 N
The normal force the ground exerts on the block,
F = - mg
= - 300 N
Hence, the normal force the ground exerts on the block, F = -300 N