All categories

3 years ago

3. | Amanda has just entered an elevator. The elevator rises and

Physics

1 answer:

rjkz [21]3 years ago

7 0

Answer:

The speed of elevator fast and slows down shows through the diagram.

Explanation:

Given that,

Amanda has just entered an elevator. The elevator rises and stops at the third floor.

Let us consider the elevator at rest then the speed will be zero.

When elevator start from rest then the speed increases with constant acceleration and near the third floor it slow down with constant deceleration and finally becomes at rest at third floor.

We need to draw the diagram distance and time

Using given data,

First, the displacement A to B will be increases fastly and B to C the displacement increases slowly slowly.

Hence, The speed of elevator fast and slows down shows through the diagram.

You might be interested in

A stone is dropped at t = 0. A second stone, with twice the mass of the first, is dropped from the same point at t = 181 ms. How

lara [203]

Answer:

the center of mass is 316,670m bellow the release point.

Explanation:

First, we must find the distance at which the objects are in time t = 360s

We will use the formula for vertical distance in free fall

$h=v_{0}t+\frac{1}{2} gt^2$

$v_{0}$ is the initial velocity, is 0 for both stones since they were just dropped.

g is acceleration of gravity and t is time ( $g=9.81m/s^2$ )

At $t=360s$ the first stone has been falling for the entire 360 seconds, its position h1 is:

$h_{1}=\frac{1}{2} (9.82m/s^2)(360s^2)=635,688m$

And at 360 seconds the second stone has been fallin for $t= 360s -181 s = 179s$ , so its position h2 is:

$h_{2}=\frac{1}{2} (9.81m/s^2)(179)^2=157,161.1m$

And finally using the equation for the center of mass:

$CM=\frac{m_{1}h_{1}+m_{2}h_{2}}{m_{1}+m_{2}}$

We know that the mass of the second stone is twice the mass of the first stone so:

$m_{1}=m\\m_{2}=2m$

replacing these values in the equation for the center of mass

$CM=\frac{mh_{1}+2mh_{2}}{m+2m}$

$CM=\frac{m(h_{1}+2h_{2})}{3m}=\frac{h_{1}+2h_{2}}{3}$

Finally, replacing the values we found fot h1 and h2:

$CM=\frac{635,688m+2(157,161.1m)}{3}=316,670m$

the center of mass is 316,670m bellow the release point.

8 0

4 years ago

The statement "for every action, there is an equal but opposite reaction" is a statement of____.

chubhunter [2.5K]

ANSWER: Isaac Newton
EXPLANATION: It is the 3rd law

3 0

3 years ago

Read 2 more answers

How far does light travel in 13 s?

Zolol [24]

Answer:

2,421,666 miles

Explanation:

light travels 186,282 miles per second in a vaccum.

So 186,282 × 13 = 2,421,666

4 0

4 years ago

Worth 15 points<br><br> Please answer which one matches for each conversion

FrozenT [24]

Answer:

distance - meters

speed - meters/seconds

time - seconds

velocity - meters/seconds

acceleration - meters/seconds²

5 0

2 years ago

The force of attraction between a -165.0 uC and +115.0 C charge is 6.00 N. What is the separation between these two charges in m

Molodets [167]

Answer:

r = 5.335 meters

Explanation:

Given that,

Charge 1, $q_1=-165\ \mu C$

Charge 2, $q_2=115\ \mu C$

Force of attraction between two charges, F = 6 N

The force of attraction between two charges is given by :

$F=k\dfrac{q_1q_2}{r^2}$ , r is the separation between two charges

$r=\sqrt{\dfrac{kq_1q_2}{F}}$

$r=\sqrt{\dfrac{9\times 10^9\times 165\times 10^{-6}\times 115\times 10^{-6}}{6}}$

r = 5.335 m

So, the separation between two charges is 5.335 meters. Hence, this is the required solution.

6 0

3 years ago