Answer:
t₁ - t₂ = 0.0011 s
Explanation:
given,
y(x, t) = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
now,
y m = 6 mm ω = 600 rad/s
y₁ = + 2.0 mm y₂ = -2 .0 mm
now,
2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
-2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
so,
kx + (600 rad/s)t₁ + Φ =
......(1)
we have multiplied with π/180 to convert angle into radians
kx + (600 rad/s)t₂ + Φ =
......(2)
subtracting both the equation (1)-(2)
600(t₁-t₂) = 
now,
t₁ - t₂ = 0.0011 s
time does any given point on the string take to move between displacements is equal to 0.0011 s
The amount of time that passes from when this skateboarder begins to slow down until she begins to move back down the incline is 8.75 seconds.
<u>Given the following data:</u>
- Acceleration = -0.2

To calculate the amount of time that passes from when this skateboarder begins to slow down until she begins to move back down the incline, we would apply the first equation of motion;
<h3>
The formula for the first equation of motion.</h3>
Mathematically, the first equation of motion for a decelerating object is given by this formula;

<u>Where:</u>
- t is the time measured in seconds.
Substituting the given parameters into the formula, we have;

Time, t = 8.75 seconds.
Read more on acceleration here: brainly.com/question/24728358
Answer:
A) ΔU = 3.9 × 10^(10) J
B) v = 8420.75 m/s
Explanation:
We are given;
Potential Difference; V = 1.3 × 10^(9) V
Charge; Q = 30 C
A) Formula for change in energy of transferred charge is given as;
ΔU = QV
Plugging in the relevant values gives;
ΔU = 30 × 1.3 × 10^(9)
ΔU = 3.9 × 10^(10) J
B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.
This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.
Thus;
P.E = K.E
ΔU = ½mv²
Where v is final velocity.
Plugging in the relevant values;
3.9 × 10^(10) = ½ × 1100 × v²
v² = [7.8 × 10^(8)]/11
v² = 70909090.9090909
v = √70909090.9090909
v = 8420.75 m/s
Answer:
-1
Explanation:
Electrons have a negative charge and protons have a positive charge. (+11) + (-12) = -1