Question

a train is moving at a constant speed on a surface and inclined at 10 degrees with the horizontal travels a distance of 400 m in 5 Seconds. calculate the vertical velocity component of the train during the time period.

Answer 1

Answer:

13.9 m/s

Explanation:

The velocity of the train along the inclined surface is given by the ratio between the distance travelled, d, and the time taken, t:

$v=\frac{d}{t}$

where we have

d = 400 m

t = 5 s

Substituting,

$v=\frac{400 m}{5 s}=80 m/s$

This is the velocity of the train along the inclined plane. Now we can find the vertical component of the velocity by using the formula:

$v_y = v sin \theta$

where $\theta=10^{\circ}$ is the angle of the slope. Substituting, we find

$v_y = (80 m/s)(sin 10^{\circ})=13.9 m/s$