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Olenka [21]
4 years ago
12

The velocity of a car teduces from 30 km/h as the car approaches a stop sigh. Is this an example of positive or negative acceler

ationthe
Physics
1 answer:
tresset_1 [31]4 years ago
5 0

<u>Answer:</u>

The stopping car has negative acceleration.

<u>Explanation:</u>

 We know acceleration is the rate of change of velocity. That is

            Acceleration(a) = ( Final velocity - Initial velocity )/ Time taken.

            Here Final velocity = 0 km/h( car stops) and initial velocity = 30 km/h

             So acceleration = (0-30)/time = -30/ time

             Time is always positive , so -30/time is negative, so the stopping car has negative acceleration.

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B C & D

Explanation:

should make you money, time well spent no time lost.

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Change to Kelvin 60 degree Celicius؟
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Explanation:

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3 years ago
Why do your feet feel colder stepping on ceramic tiles than on carpet?
gregori [183]

Answer:

Option B

Tile is a good conductor : a carpet is a good insulator

Explanation:

When the feet comes in contact with the tile, the tile conducts heat from the body making one to feel cold. However, since carpet is made of insulators such as cotton, they don't conduct heat, therefore, it slows down the flow of the heat which would make it feel warm so our feet do not feel much more colder as it does with the tiles.

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4 years ago
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You are standing 30 m from a window that is 30 m off the ground. Your friend tries to toss you something, but only throws it str
pochemuha

Answer:

minimum initial velocity is 21.35 m/s

Explanation:

given data

distance S = 30 m

height h = 30 m

maximum acceleration a = 2 m/s²

to find out

minimum initial velocity that your friend could have thrown the object to enable you to catch

solution

first we get here time with the help of second equation of motion

time = \sqrt{\frac{2h}{a} }  ..................1

put her value we get

time = \sqrt{\frac{2*30}{2} }

time = 5.477 second

and that is time which tossed object must be take so we apply here again second equation of motion that is

-S = ut - 0.5 × gt²   .......................2

-30 = u× 5.477 - 0.5 ×9.8×5.477²

solve it we get

u = 21.35 m/s

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3 0
3 years ago
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A pebble is dropped from rest from the top of a tall cliff and falls 53.4 m after 3.3 s has elapsed. How much farther does it dr
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Answer:

426.84 m

Explanation:

initial velocity u = 0

time t = 3.3 s

distance travelled s = 53.4 m

acceleration due to gravity = g

s = ut + 1/2 g t²

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g = 9.8 m /s²

For the whole length of fall

distance travelled = h

total time = 6.6 + 3.3 = 9.9 s

h = ut + 1/2 g t²

u again = 0

h = .5 x 9.8 x 9.9²

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= 480.24 - 53.4

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6 0
3 years ago
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