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Gwar [14]
3 years ago
8

there are approximately 202 gallons per cubic yard of water write and solve an equation for the number of gallons of water to fi

ll a pool with a volume of 1161 cubic feet
Mathematics
1 answer:
Setler [38]3 years ago
8 0

The Volume  of the  Swimming pool is  : 1161 cubic feet

The water in the 1 cubic yard  =  202 gallons

Let us first change 1 cubic  yard into 1 cubic feet

We know 1 yard = 3 foot

                 1 cubic yard =  3*3*3   cubic feet

                1 cubic yard =  9 cubic feet .

Water in the  9 cubic feet = 202  gallons

water  in the 1  cubic feet = 202/9  = 22.44 gallons


Let us suppose  there is x gallon water  in the swimming pool

so    volume of  the  swimming pool  in cubic feet * volume of the water in 1 cubic feet =  x gallon

         1161 * 22.44  = x

  26058 gallons = x  

Answer :  26058 gallons of water is required to fill the  swimming pool .

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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25  

And rounded up we have that n=421

Step-by-step explanation:

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

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And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that a prior estimation for p would be \hat p =0.5 since we don't have any other info provided. And replacing into equation (b) the values from part a we got:

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<h2>Answer:</h2><h2>ADD 53+1 </h2>

Step-by-step explanation:

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