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2 years ago

Help 6th grade math i will give brainliest

Mathematics

2 answers:

eimsori [14]2 years ago

5 0

<h2>Answer:</h2><h2>ADD 53+1 </h2>

Step-by-step explanation:

plz give brainlyest

4* 53+1/(8-5)^3

4(54)/(8−5)3

4(54/3^3)

4(54/27)

(4)(2)=8 the answer is 8

Burka [1]2 years ago

4 0

Answer:

Add 53 + 1

Step-by-step explanation:

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The scatterplot that shows a negative linear association between the variables is B

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This is worth 20 points please help now it is an emergency. Please do 1 through 10

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3 years ago

rectangle DOIT has vertices at D(-20,3) O(20,3) I(20,-6) T(-20,-6) what is the area of rectangle DOIT

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2 years ago

The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St

saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(domestic airfare is $550 or more)

P(x > 550)

$P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)$

$= 1 - P(z \leq 1.5)$

Calculation the value from standard normal z table, we have,

$P(x > 550) = 1 - 0.933 = 0.067= 6.7\%$

b) P(domestic airfare is $250 or less)

$P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)$

Calculating the value from the standard normal table we have,

$P( x \leq 250) = 0.111 = 11.1\%$

c))P(domestic airfare is between $300 and $500)

$P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%$

$P(300 \leq x \leq 500) = 61.2\%$

d) P(X=x) = 0.03

We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 385}{110})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 385}{110})=0.03$

$=P( z \leq \displaystyle\frac{x - 385}{110})=0.997$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 385}{110} = 2.748\\x = 687.28$

Hence, the domestic fares must be $687.28 or greater for them to lie in the highest 3%.

7 0

3 years ago

-5f-2+8-3k use f=7 and k=8

yaroslaw [1]

You have to plug in 7 for f and 8 for k making it look like -5(7)-2+8-3(8), now multiply to get the further more, -35-2+8-24, now add or subtract to get -53

Hope this helps

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3 years ago

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