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strojnjashka [21]
3 years ago
13

ENTS

Mathematics
2 answers:
Crazy boy [7]3 years ago
7 0

Answer: D.

Step-by-step explanation:

I am Lyosha [343]3 years ago
5 0

Answer:

B

Step-by-step explanation:

i took the test on usatestprep

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Assume the line between (-4, 4) and (-4, -4) will form one side of a right triangle. When (-4, 4) is reflected over both axes to
telo118 [61]

Answer:

8 units!!

Step-by-step explanation: When the coordinates are reflected in both axes, it is technically just going diagonally. And 'base' means perimeter. so that is your answer. :)

7 0
3 years ago
Do 4x and 15 + x have the same value if x is 5?
Cerrena [4.2K]
Yes because 4 times 5 is 20 and 15 + 5 is 20
4 0
2 years ago
Determine the nth term for each of the following sequences: 2,5,8,11,14,..
Tanya [424]
To determine the nth term, we must create a function.

f(n) = 1st term + common difference (n - 1)

n = term you are looking for
1st term = 1st number in the sequence
common difference = the difference between two consecutive numbers in the sequence.

based on the above sequence, the 1st term is 2, its common difference is 3.

f(n) = 2 + 3(n-1)

Assuming we are looking for the 5th term
f(5) = 2 + 3(5-1)
       = 2 + 3(4)
       = 2 + 12
f(5) = 14   as you can see in the above sequence 14 is the 5th term.

For any other value of the nth term, simply substitute n by the number of the term and solve the equation.
8 0
3 years ago
Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
lianna [129]
<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

   Let the complex numbers be a+ib\textrm{ and }c+id.

Given, sum is 10i, difference is -4 and product is -29.

(a+c)+i(b+d)=10i ⇒ a+c=0,b+d=10

(a-c)+i(b-d)=-4 ⇒ a-c=-4,b-d=0

a=-2,c=2,b=5,d=5

(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

Hence, all three equations are consistent yielding the complex numbers -2+5i\textrm{ and }2+5i.

8 0
3 years ago
For the function f(x)=(x+6)^3, rind f^-1(x)
qaws [65]

Answer:

f^{-1}(x)=\sqrt[3]{x}-6

Step-by-step explanation:

f(x)=(x+6)^3

y=(x+6)^3

x=(y+6)^3

\sqrt[3]{x}=y+6

\sqrt[3]{x}-6=y

5 0
3 years ago
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