Answer:
33.30 grams of CaCl2 will be required
Explanation:
Given,
Volume of solution, V= 250 ml
Molarity of solution, M= 1.20 mol/L
Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111
We know,
Required mass, W= SVM/1000
Now,
W = (111 X 250 X 1.20)/1000
= 33300/1000
= 33.30
Therefore, 33.30 grams of Calcium Chloride will be required.
NaCl
HCI is a poiar covalent compound while ℂI4 is a non-polar covalent compound because both are iormed by sharing of electrons. KCl and NaCl are formed by the transfer of electrons and are ionic compounds.
Cambrian, Ordovician, Silurian, Devonian, Carboniferous, and Permian
These all occurred in the paleozoic Era I hope you do great good luck <3
up draft of air
19.6 g is the mass of methanol
Density of methanol is 0.787 g/mL.
Density means mass / volume
Methanol density = Methanol mass / Methanol volume.
Let's replace in the formula
0.787 g/mL = Methanol mass / 25 mL
0.787 g/mL . 25 mL = Methanol mass → 19.6 g
