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Stolb23 [73]
4 years ago
12

An article claims that 12% of trees are infested by a bark beetle. A random sample of 1,000 trees were tested for traces of the

infestation and found that 127 trees were affected.
z = p - p/p q/n
Using the formula and data provided, what is the value of the z-test statistic?
Mathematics
1 answer:
inna [77]4 years ago
7 0

Answer: 0.6812

Step-by-step explanation:

Let p be the population proportion of trees are infested by a bark beetle.

As per given: p= 12%= 0.12

Sample size : n= 1000

Number of trees affected in sample = 1000

Sample proportion of trees are infested by a bark beetle. = \hat{p}=\dfrac{127}{1000}=0.127

Now, the z-test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

So, z=\dfrac{0.127-0.12}{\sqrt{\dfrac{0.12\times 0.88}{1000}}}

z=\dfrac{0.007}{\sqrt{\dfrac{0.1056}{1000}}}\\\\\\=\dfrac{0.007}{\sqrt{0.0001056}}\\\\\\=\dfrac{0.007}{0.010276}\approx0.6812

Hence, the value of the z-test statistic = 0.6812 .

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Answer:

200 visitors went to screen 1.

125 visitors went to screen 2.

175 visitors went to screen 3.

Step-by-step explanation:

We will find number of visitors who went to screen 1 by finding 40% of 500 as we are told that 40% of 500 visitors went to screen 1.

500*\frac{40}{100} =5*40=200

Therefore, 200 visitors went to screen 1.

Now we will find number of visitors who went to screen 2. We are told that 25% of 500 visitors went to screen 2.

500*\frac{25}{100} =5*25=125

Therefore, 125 visitors went to screen 2.

Now we will find the number of visitors who went to screen 3 by subtracting combined number of visitors who went to screen 1 and screen 2 from total number of visitors.

500-(200+125)

500-325=175

Therefore, 175 visitors went to screen 3.


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