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san4es73 [151]
3 years ago
15

Mr. Sasha teaches 4 math classes, with the same number of students in each class. Of those students, 80 are sixth graders and 40

are fifth graders. Write an equation to determine whether there are 22, 25, or 30 students in each class. How many are in each class?
Mathematics
1 answer:
STatiana [176]3 years ago
6 0
80=6th graders
40=5th graders

80+40=120
120/22= 60/11
120/25=24/5
120/30= 4

There are 30 students in each class because he teaches 4 class and 120/30 will give you 4.
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Answer:

-x + -13

Step-by-step explanation:

Rewrite: 5(x – 4) + 3x – 9x + 7

Step 1: 5(x + –4) + 3x + –9x + 7

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Step 3: 5x + 3x + –9x + -20 + 7

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-4x+3+2x-6
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3 years ago
A car salesman makes 10% commission on the first $ 10,000 and 12% on the remaining the 12,500 of his sales. How much commission
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6 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

4 0
3 years ago
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