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Vladimir [108]
3 years ago
14

Select the correct answer.

Chemistry
1 answer:
elena-s [515]3 years ago
5 0

Answer:

B. CO + H₂O → H₂ + CO₂

Explanation:

Redox reaction -

It is the type of reaction , where the process of oxidation and reduction takes place simultaneously , is known as a redox reaction .

Oxidation refers to the addition of oxygen atom or the removal of hydrogen atom .

And ,

Reduction refers to the addition of hydrogen atom or the removal of the oxygen atom .

From the options given in the question , the only reaction , which have both the process of oxidation as well as reduction , is  -

CO + H₂O → H₂ + CO₂

In the above reaction ,

Oxidation process -  CO → CO₂ ,

The addition of oxygen atom .

Reduction process - H₂O → H₂ ,

The removal of oxygen atom .

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POSSIB
siniylev [52]

Answer:

96.99 C degree change

Explanation:

  480 cal  / ( 150 g * .033 cal/g-C )  = 96.99 C

8 0
2 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
3 years ago
How to I answer this question! Not looking for the answers for the question just how to solve it myself!
Mrac [35]
I have not taken Chemistry in a year but I remember that if you look at a periodic table there are certain sections for polar and non polar elements. I dont know if you have learned that yet
7 0
3 years ago
Read 2 more answers
This body system is where oxygen gas and carbon dioxide gas are exchanged in our body. *
nexus9112 [7]

Answer:

The answer is the respiratory system

Explanation:

The function of the respiratory system is to move two gases. These two gases are called oxygen and carbon dioxide. Gas exchange takes place in the millions of alveoli in the lungs and the capillaries that envelop them.

6 0
4 years ago
Read 2 more answers
How many grams of HF are needed to react with 3.0 moles of Sn? *
Lostsunrise [7]

Answer:

120g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Sn + 2HF —> SnF2 + H2

Next, we shall determine the number of mole of HF needed to react with 3 moles of Sn.

From the balanced equation above, 1 mole of Sn reacted with 2 moles of HF.

Therefore, 3 moles of Sn will react with = 3 x 2 = 6 moles of HF.

Finally, we shall convert 6moles of HF to grams

This is illustrated below:

Number of mole of HF = 6moles

Molar Mass of HF = 1 + 19 = 20g/mol

Mass of HF =..?

Mass = number of mole x molar Mass

Mass of HF = 6 x 20

Mass of HF = 120g

Therefore, 120g of HF is needed to react with 3 moles of Sn

6 0
3 years ago
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