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vitfil [10]
3 years ago
15

Many homeowners treat their lawns with CaCO3(s) to reduce the acidity of the soil. Write a net ionic equation for the reaction o

f CaCO3(s) with a strong acid.
Chemistry
1 answer:
Aliun [14]3 years ago
3 0

Many homeowners treat their lawns with CaCO3(s) to reduce the acidity of the soil. The net ionic equation for the reaction of CaCO3(s) with a strong acid, HCl (I chose HCl because it is a strong acid) is CaCO3(s) +2 HCl(aq) → CaCl2(s) + H2O(aq) + CO2(g).

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Helppppp pleaseeee xxxxxx
kogti [31]

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

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The CH4 molecule has the lowest molecular weight, so it has the lowest boiling point.

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