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Ilia_Sergeevich [38]
3 years ago
10

How do i answer this

Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0
Wherever there is an x , plug in 20,000
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6.3 + |8.7 + (-6.8)|
igor_vitrenko [27]

Answer:

21.8

Step-by-step explanation:

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Oscar uses place value to divide 63.81 by 9 his steps are shiwn below what mistake does oscar make
Ksenya-84 [330]

Check the picture below.

6 0
3 years ago
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What is the measure of angle c? (Brainliest and Bonus points for best answer)
k0ka [10]

Answer:

\displaystyle 65°

Step-by-step explanation:

Angle <em>b</em> and 135° form a <em>linear pair</em>, so when summing them up to 180°, you will have 45° left over:

\displaystyle 180° = 135° + m∠b; 45° = m∠b

Now, by the <em>Vertical</em><em> </em><em>Angles</em><em> </em><em>Theorem</em>, angle <em>a</em> and 70°, in this case, are to be in <u>congruence</u> with each other, so you have that.

Now you must find the the measure of angle <em>c</em> sinse you have already found the measure of two angles already:

\displaystyle 180° = 45° + m∠c + 70° → 180° = 115° + m∠c; 65° = m∠c

I am joyous to assist you at any time.

3 0
3 years ago
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What is an interval scale and what is it used for?
koban [17]
An interval scale has measurements where the difference between values is meaningful. For example, the year 0 doesn’t imply that time didn’t exist. And similarly, a temperature of zero doesn’t mean that temperature doesn’t exist at that point. Arbitrary zeros (and the inability to calculate ratios because of it) are one reason why the ratio scale — which does have meaningful zeros — is sometimes preferred.
8 0
3 years ago
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Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
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