Given P(E) = 0.24 and P(F ∩ E) = 0.17
It says to find conditional probability of F given E has occurred.
We know the formula of conditional probability is given by :-
P(F ║ E) =
P(F ║ E) = = 0.708333
P(F ║ E) = 0.71
Hence, option C i.e. 0.71 is the final answer.
Answer:
The quotient contains a terminating decimal and The quotient is a whole number less than 11.
Step-by-step explanation:
To answer this one, it's mandatory to remember that quotient, is the outcome of a ratio: a number (r) over another (s) (different than 0). In this case:. So q is equal to =0.08823529411.
Analyzing the number: 0.08823529411
This is not a repeating decimal, but it is a terminating decimal for it has an end.
The quotient is also a whole number less than 11.
The Whole Set of numbers is made up of the following numbers W ={0,1,2,...} and 0 < 11. Therefore it is true.