Hello! In order to understand this question, we need to take a look at the content that is involved.
Lupita pays $40.03 in total. Meaning that's where we are going to start if we want to find out how many miles her ride was. Since the taxi charges a flat rate of $6.75. We would want to subtract it from her total value because we only work with that flat rate once. Which ends up giving us $33.28. From there, we don't need to worry about the flat rate anymore and we now focus on the mileage. If it costs $3.20 per mile, then we can simply divide the amount after to flat rate by the cost per mile, to figure out how many miles she has gone. In the end, you will get 10.4 miles.
Answer:
increase
Step-by-step explanation:
First, we need to find the mean of the given data set without any change.
10 + 61 + 10 + 44 + 21 + 79 + 27 + 12 = 264
264 ÷ 8 = <u>33</u>
Now that we have the mean, we can find the mean of the data set with the change of 52.
10 + 61 + 10 + 44 + 21 + 79 + 27 + 52 = 304
304 ÷ 8 = <u>38</u>
<u />
From this, we can see that the mean has increased with the change of 12 to 52. Thus, that's the correct option.
hope this helps!
Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater
so "b" is "4 more than 5 times" "a"
so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4
so.. whatever "a" is, "b" is 5a+4
now, their sum is 22, as opposed to "zz" hehe
so

solve for "a", to see what the smaller one is
what's "b"? well, b = 5a + 4
I believe C. Measuring the length from one end of the field tot he other would be the most reasonable answer, because Area = Length x Width
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>√</em><em>7</em><em>4</em><em> </em><em>units</em><em>.</em>
<em>Pl</em><em>ease</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> full</em><em> solution</em>
<em>H</em><em>ope</em><em> it</em><em> helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>