Question

Check all of the following that are solutions to the system shown below.

Answer 1

Answer:

(2,-4),(-2,0)

Step-by-step explanation:

       Given system of equations :

$y=-x^{2}-x+2;x+y=-2$

On substituting $y=-2-x$ from second equation in the first equation,

$-2-x=-x^{2}-x+2\\x^{2}=4\\x=\pm2$

       From first equation, when $x=2$, $y=-4$;

when $x=-2$, $y=0$

∴ $x=2,y=-4$ and $x=-2,y=0$ are the solutions to the system given.