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LiRa [457]
3 years ago
5

Air-bags can be inflated by the decomposition of sodium azide, NaN3. At 25.0◦C and 1.10 atm, what volume of N2(g) is produced by

the decomposition of 71.4 g NaN3 under the following chemical reaction: 2NaN3(s) → 2Na(l) + 3N2(g)
Chemistry
1 answer:
Mashcka [7]3 years ago
4 0

Answer:

V = 36.7L of N_{2}

Explanation:

1. Write the chemical reaction for the decomposition of sodium azide:

_{2}NaN_{3}(l)=_{2}Na(s)+_{3}N_{2}(g)

2. Find the number of moles of N_{2} produced by the decomposition of 71.4g of NaN_{3}:

71.4gNaN_{3}*\frac{1molNaN_{3}}{65gNaN_{3}}*\frac{3molesN_{2}}{2molesNaN_{3}}=1.65molesN_{2}

3. Use the ideal gas equation to find the Volume of N_{2} occupied by 1.65 moles of N_{2}, at the temperature and pressure given by the problem:

PV=nRT

Solving for V:

V=\frac{nRT}{P}

Converting the temperature from ◦C to K:

25◦C+273.15=298.15K

Replacing values:

V=\frac{1.65mol*(0.082\frac{atm.L}{mol.K})*298.15K}{1.10atm}

V=36.7L of N_{2}

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sveticcg [70]

Answer:

Reaction is already balanced

Explanation:

The equation in reaction 1 is given as;

CH3COOH + NaHCO3 --> CO2 + H2O +  Na+   +  CH3COO-

The reaction is already balanced. This is because the umber of atoms of elements in the reactant is equal to that of the products

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Reactant = 2 + 1 = 3

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Sodium

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Product = 1

3 0
3 years ago
How many atoms are in 13.97 liters of water vapor at STP
Arisa [49]
<span>Let's </span>assume that water vapor has ideal gas behavior. <span>
Then we can use ideal gas formula,
PV = nRT<span>

</span><span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span></span>⁻¹ K⁻¹) and T is temperature in Kelvin.<span>
<span>
</span>P = 1 atm = 101325 Pa (standard pressure)
V = 13.97 L = 13.97 x 10</span>⁻³ m³<span>
n = ?
R = 8.314 J mol</span>⁻¹ K⁻¹<span>
T = 0 °C = 273 K (standard temperature)
<span>
By substitution,
</span>101325 Pa x 13.97x 10</span>⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 273 K<span>
                                          n = 0.624 mol
<span>
Hence, the moles of water vapor at STP is 0.624 mol.

According to the </span></span>Avogadro's constant, 1 mole of substance has 6.022 × 10²³ particles.
<span>
Hence, number of atoms in water vapor = 0.624 mol x </span>6.022 × 10²³ mol⁻¹
<span>                                                                = 3.758 x 10</span>²³<span>

</span>
5 0
3 years ago
25 °C = ________ K <br><br> which one <br> 298<br> 0<br> 33 <br> 197
Paraphin [41]

Answer:

298

hope this helps

have a good day :)

Explanation:

5 0
3 years ago
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Which has not been a major source of CFCs
ipn [44]

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4 0
4 years ago
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A graduated cylinder was filled with water to the 25.0 mL mark and weighed. Its mass was 105.5g. An object made of an unknown me
Marta_Voda [28]
The answer <span>is <span>8.9 g/mL</span>.</span>

The density (D) is <span>equal to mass (m) divided by volume (V): D = m/V

Let's find the mass of the object:
m = 156 g - 105.5 g = 50.5 g

Let's find the volume of the volume:
V = 30.7 mL - 25 mL = 5.7 mL

The density is:
D = m/V = 50.5 g  / 5.7 mL = 8.9 g/mL</span>
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