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3 years ago

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Physics Question (attached)

1 answer:

hammer [34]3 years ago

8 0

Answer:

The answer is " $\bold{10.6 \ \ \frac{m}{s^2}}$ "

Explanation:

The Formula of acceleration:

$\bold{a= \frac{v-v_0}{t}}$

Given value:

$t= 50\\v= 856\\v_0= 324$

Calculating the acceleration:

$\to a = \frac{(856 - 324)}{50}\\\\$

$= \frac{(532)}{50}\\\\= \frac{(106.4)}{10}\\\\= 10.64 \ \ \frac{ m}{s^2}$

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What are the names of the 2 charged particles in an atom and what are their charges

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Answer:

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Explanation:

Given:

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$m_A.v_A+m_B.v_B=0$

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Put the value of $v_A$ from eq. (2) into eq. (1)

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$KE_B=\frac{1}{2}\times m_B\times v_B^2$

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<u>Now the kinetic energy of particle A:</u>

<u /> $KE_A=\frac{1}{2}m_A.v_A^2$ <u />

<u /> $KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}$ <u />

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