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nika2105 [10]
3 years ago
5

A closed-end manometer was attached to a vessel containing argon. The difference in the mercury levels in the two arms of the ma

nometer was 12.2 cm. Atmospheric pressure was 783 mmHg. The pressure of the argon in the container was __________ mmHg.
Physics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

122 mmHg

Explanation:

In the given problem, the height of the column will not be affected by the atmospheric pressure because the manometer end is closed.

The difference of height of the mercury level is given as,

h=12.2cm\\h=12.2(\frac{10mm}{1cm})\\ h=122mm

Now as we know that the pressure of the gas is equal to the height in the case of closed end manometer.

P_{gas}=h

Therefore,

P_{gas}=122 mmHg

This pressure is caused due to the presence of gas.

Therefore, the pressure of the argon gas in the container is 122 mmHg.

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A 1200 kg car traveling east at 4.5 m/s crashes into the side of a 2100 kg truck that is not moving. During the collision, the v
Rasek [7]

Answer:

Explanation:

This is a simple Law of Momentum Conservation problem of the inelastic type. The equation for this is

[m_1v_1+m_2v_2]_b=[(m_1+m_2)v]_a  Filling in:

[1200(4.5)+2100(0)]=[(1200+2100)v] which simplifies to

5400 + 0 = 3300v

so v = 1.6 m/s to the east, choice B

6 0
2 years ago
A dog has a mass of 20 kg. If the dog is pushed across the ice with a force of 40 N, what is its acceleration?
olasank [31]

Answer:

The acceleration is 2 m/s2.

Explanation:

We calculate the acceleration (a), with the data of mass (m) and force (F), through the formula:

F = m x a  ---> a= F/m

a = 40 N/20 kg                   <em>  1N= 1 kg x m/s2</em>

a= 40 kgx m/s2/ 20 kg

<em>a= 2 m/s2</em>

7 0
3 years ago
Calculate the mass 9f the earth, assuring that uts is sphere with radius 6.67×10^6m.​
MA_775_DIABLO [31]

Answer:

6.86 × 10²⁴ kg

Explanation:

The mass of the earth m = density of earth, ρ × volume of earth, V

m = ρV

The density of the earth, ρ = 5515 kg/m³ and since the earth is a sphere, its volume is the volume of a sphere V = 4πr³/3 where r = radius of the earth = 6.67 × 10⁶ m

Since m = ρV

m = ρ4πr³/3

So, substituting the values of the variables into the equation for the mass of the earth, m, we have

m = 5515 kg/m³ × 4π(6.67 × 10⁶ m)³/3

m = 5515 kg/m³ × 4π × 296.741 × 10¹⁸ m³/3

m = 5515 kg/m³ × 1189.9639π × 10¹⁸ m³/3

m = 6546105.64378π × 10¹⁸ kg/3

m = 20565197.400122 × 10¹⁸ kg/3

m = 6855065.8 × 10¹⁸ kg

m = 6.8550658 × 10²⁴ kg

m ≅ 6.86 × 10²⁴ kg

8 0
3 years ago
The work output of a machine divided by the work input is the ____ of the machine.
s344n2d4d5 [400]
<span>The work output of a machine divided by the work input is the "Efficiency" of the machine.

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7 0
3 years ago
Determine the potential difference between the ends of the wire of resistance 5 Ω if 720 C passes through it per minute.
Strike441 [17]

Answer:

The potential difference between the ends of a wire is 60 volts.

Explanation:

It is given that,

Resistance, R = 5 ohms

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Time, t = 1 min = 60 s

We know that the charge flowing per unit charge is called current in the circuit. It is given by :

I = 12 A

Let V is the potential difference between the ends of a wire. It can be calculated using Ohm's law as :

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V = 60 Volts

So, the potential difference between the ends of a wire is 60 volts. Hence, this is the required solution.

8 0
3 years ago
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