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3 years ago

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A closed-end manometer was attached to a vessel containing argon. The difference in the mercury levels in the two arms of the ma

nometer was 12.2 cm. Atmospheric pressure was 783 mmHg. The pressure of the argon in the container was __________ mmHg.

1 answer:

timurjin [86]3 years ago

5 0

Answer:

122 mmHg

Explanation:

In the given problem, the height of the column will not be affected by the atmospheric pressure because the manometer end is closed.

The difference of height of the mercury level is given as,

$h=12.2cm\\h=12.2(\frac{10mm}{1cm})\\ h=122mm$

Now as we know that the pressure of the gas is equal to the height in the case of closed end manometer.

$P_{gas}=h$

Therefore,

$P_{gas}=122 mmHg$

This pressure is caused due to the presence of gas.

Therefore, the pressure of the argon gas in the container is 122 mmHg.

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Than means that the lowest current will be registered through branch D where the 50 $\Omega$ resistor is.

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