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nika2105 [10]
3 years ago
5

A closed-end manometer was attached to a vessel containing argon. The difference in the mercury levels in the two arms of the ma

nometer was 12.2 cm. Atmospheric pressure was 783 mmHg. The pressure of the argon in the container was __________ mmHg.
Physics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

122 mmHg

Explanation:

In the given problem, the height of the column will not be affected by the atmospheric pressure because the manometer end is closed.

The difference of height of the mercury level is given as,

h=12.2cm\\h=12.2(\frac{10mm}{1cm})\\ h=122mm

Now as we know that the pressure of the gas is equal to the height in the case of closed end manometer.

P_{gas}=h

Therefore,

P_{gas}=122 mmHg

This pressure is caused due to the presence of gas.

Therefore, the pressure of the argon gas in the container is 122 mmHg.

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A diagram of a closed circuit with a power source on the left labeled 6 V. There are 3 resistors in parallel, separate paths, co
AfilCa [17]

Answer:

Current: 1.0 Amperes

The minimum current is flowing through path D

Explanation:

We first find the equivalent resistance to the three resistors in parallel ( which is the total resistance of the circuit) via the equation:

\frac{1}{R_e} =\frac{1}{R_B}+\frac{1}{R_C}+\frac{1}{R_D}\\\frac{1}{R_e} =\frac{1}{10}+\frac{1}{20}+\frac{1}{50}=0.17\\R_e=(1/0.17)\Omega\\R_e=5.88 \Omega

with this info, we can estimate the current going through branch A using Ohm's Law, and the information that the power source is 6 V:

V=I*R\\6V=I*5.88\Omega\\I=\frac{6}{5.88} Amp\\I=1.02A

where the current comes in units of Amperes since all other the quantities are given in the SI system, and we can round this answer to 1.0 Amp following the request to round it to the tenth.

The current will be the lowest through the branch with the largest resistor due to the fact that less current will flow through the path of more resistance.

Than means that the lowest current will be registered through branch D where the 50 \Omega resistor is.

8 0
3 years ago
Read 2 more answers
आप शोर मत करिए। किस प्रकार का वाक्य है- *​
Law Incorporation [45]

Answer:

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Explanation:

7 0
3 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You have a stopped pipe of adjustable length clo
faltersainse [42]

Answer:

Length of pipe = 0.057 meter

Explanation:

Speed of a transverse wave on a string

v = \sqrt{\frac{F}{\mu} }

where F is the tension in string and \mu is the mass per unit length

Thus,

\mu = \frac{m}{L}

Substituting the given values we get -

\mu = \frac{7.25 * 10^{-3}}{0.62}\\mu = 0.0117 \frac{Kg}{m}

Speed of a transverse wave on a string

v = \sqrt{\frac{4510}{0.0117} } \\v = 620.86 \frac{m}{s}

For third harmonic wave , frequency is equal to

f = \frac{nv}{2L}

Substituting the given values, we get -

f = \frac{3 * 620.86}{2 * 0.62} \\f = 1502.08

Length of pipe

L = \frac{nv}{4 f}

Substituting the given values we get

n = 1 for first harmonic wave

L = \frac{344* 1}{4*1502.08} \\L = 0.057

Length of pipe = 0.057 meter

5 0
3 years ago
HELP PLS .. The half-life of potassium-44 is 22 minutes. It decays into calcium-44. After
Ber [7]

Answer:

1/4

Explanation:

3 0
2 years ago
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The distribution circuit of a residential power line is operated at 2000 V rms. This voltage must be reduced to 240 V rms for us
forsale [732]

Answer:

N_p\approx3958

Explanation:

In an ideal transformer the relationship between the voltages is proportional to the ratio between the number of turns of the windings. Thus:

\frac{V_p}{V_s} =\frac{N_p}{N_s}

Where:

V_p=Voltage\hspace{3}in\hspace{3}primary\hspace{3}coil

V_s=Voltage\hspace{3}in\hspace{3}secondary\hspace{3}coil

N_p=Turns\hspace{3}on\hspace{3}primary\hspace{3}coil

N_s=Turns\hspace{3}on\hspace{3}secondary\hspace{3}coil

So, solving for N_p

N_p=N_s*\frac{V_p}{V_s} =475*\frac{2000}{240} =3958.333333\approx3958

7 0
3 years ago
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