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3 years ago

What is the difference between a permanent magnet and a temporary magnet

2 answers:

7 0

A permanent magnet does not loose its magnetism easily. It can only be lost by permanent destruction say by fire. Example of this is magnetism from a bar magnet. This magnetism is not induced by say electric current.

A temporary magnet looses its magnetism easily. The magnetism is gained or loosed for the action of carrying out a particular task. This magnetism can be achieved by the gain or loss by passing of electric current over say an iron core.

lara31 [8.8K]3 years ago

4 0

Pernament magnet is one that retains its magnetic properties for a long period of time. Temporary megnet only maintains its magnetism while in a magnetic field produced by permanent magnet or electric current.

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1. Place these unknown pH test papers in order from most acidic to most alkaline.

Naddika [18.5K]

Answer: B

Explanation: look at the chart, easy

7 0

3 years ago

A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.10 m. (a) Calculate its ve

Gemiola [76]

Answer:

(a) v = 5.42m/s

(b) vo = 4.64m/s

(d) Δy = 5.11*10^-3m

Explanation:

(a) The velocity of the ball before it hits the floor is given by:

$v=\sqrt{2gh}$ (1)

g: gravitational acceleration = 9.8m/s^2

h: height where the ball falls down = 1.50m

$v=\sqrt{2(9.8m/s^2)(1.50m)}=5.42\frac{m}{s}$

The speed of the ball is 5.42m/s

(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.

You use the following formula:

$h_{max}=\frac{v_o^2}{2g}$ (2)

vo: velocity of the ball where it starts its motion upward

You solve for vo and replace the values of the parameters:

$v_o=\sqrt{2gh_{max}}=\sqrt{2(9.8m/s^2)(1.10m)}=4.64\frac{m}{s}$

The velocity of the ball is 4.64m/s

(c) The acceleration is given by:

$a=\frac{\Delta v}{\Delta t}=\frac{v_o-v}{3.50*10^{-3}s}=\frac{4.64m/s-(-5.42m)/s}{3.50*10^{-3}s}=2874.285\frac{m}{s^2}$

$a=\frac{\Delta v}{\Delta t}=\frac{v_o-v}{3.50*10^{-3}s}=\frac{4.64m/s-5.42m/s}{3.50*10^{-3}s}=-222.85\frac{m}{s^2}$

The acceleration of the ball is 2874.28/s^2

(d) The compression of the ball is:

$\Deta y=\frac{v^2}{2(a)}=\frac{(5.42m/s)^2}{2(2874.28m/s^2)}=5.11*10^{-3}m$

THe compression of the ball when it strikes the floor is 5.11*10^-3m

4 0

3 years ago

Fill in the blank

aliina [53]

Answer:

hypothesis

Explanation:

8 0

3 years ago

Help please <br><br><br> What is elastic potential energy

spin [16.1K]

Awnser:

Elastic Potential Energy. Elastic potential energy is Potential energy stored as a result of deformation of an elastic object,

Explanation:

4 0

3 years ago

A body travels 30m in 5s, 45m in 7s and then 65m in the last 5s. Find the average speed of the body

JulijaS [17]

We can find the average speed of the body by finding the total distance covered, and then dividing it by the total time of the motion.

The total distance covered is:
$S=30 m + 45m+65m=140 m$

while the total time of the motion is
$t=5 s+7s+5 s=17 s$

So, the average speed of the body is:
$v= \frac{S}{t}= \frac{140 m}{17 s}=8.24 m/s$

8 0

3 years ago