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LenKa [72]
3 years ago
12

An object is held at a distance of 20cm from a concave lens of focal length 80cm. What is the

Physics
1 answer:
Sladkaya [172]3 years ago
5 0
<h3>Answer</h3>

it is -16

<h2>explanation </h2><h3>Here, u=−20cm,f=−80cm,v=?,h1=2cm,h2=?</h3><h3>From 1v−1u=1f,1v=1f+1u=1−80−120=−1−480=−580</h3><h3>v=−805=−16cm.</h3><h3>Thus, image is at 16 cm from the lens on the same side as the object.</h3><h3>As h2h1=vu∴h2=vuh1=−16−20×2cm=1.6cm</h3><h3>This is the size of the image.</h3>
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State<br><br> What is the correct order of tasks for washing dishes in a three-compartment sink?
Nataliya [291]

Answer:

The summary of the given statement is explained below throughout the explanation segment.

Explanation:

  • Drain certain surfaces throughout warm water of such soap during the very first sink. This same sanitizing of bacteria would not destroy whether grime would be in the direction.
  • Exfoliate the plates throughout plain water during the secondary drain. As with grime, the residual soap could avoid the kill off bacteria and viruses by the sanitizer.
7 0
3 years ago
What is the instantaneous speed at 5 seconds? (remember s=d/t)
TEA [102]
5 seconds is a poor time to ask about, because the speed abruptly changes at exactly 5 seconds.

Up until that time, the speed has been 1 m/s. And then, at exactly 5 seconds, it becomes zero.
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It's also a poor question because speed is calculated from the distance covered, but the graph shows displacement, not distance. You can't really tell the distance covered from a displacement graph. For example, if an object happens to be moving in a circle around the place where it started, then the total distance covered keeps increasing, but its displacement is constant.
4 0
3 years ago
Read 2 more answers
The constant forces F1 = 8 + 29 + 32 N and F2 = 48 - 59 - 22 N act together on a particle during a displacement from the point A
steposvetlana [31]

Answer:

- 600 J

Explanation:

A (20, 15, 0 ) m

B (0, 0, 7) m

\overrightarrow{F_{1}}=8\widehat{i}+29\widehat{j}+32\widehat{k}

\overrightarrow{F_{2}}=48\widehat{i}-59\widehat{j}-22\widehat{k}

Net force

\overrightarrow{F}=\overrightarrow{F_{1}}+\overrightarrow{F_{2}}

\overrightarrow{F}}=\left ( 8+48 \right )\widehat{i}+\left ( 29-59 \right )\widehat{j}+\left ( 32-22 \right )\widehat{k}

\overrightarrow{F}}=56\widehat{i}-30\widehat{j}+10\widehat{k}

\overrightarrow{S}=\overrightarrow{OB}-\overrightarrow{OA}

\overrightarrow{S}=\left ( 0-20 \right )\widehat{i}+\left ( 0-15 \right )\widehat{j}+\left ( 7-0 \right )\widehat{k}

\overrightarrow{S}=-20\widehat{i}-15\widehat{j}+7\widehat{k}

Work done is defined as

W = \overrightarrow{F}.\overrightarrow{S}

W = \left ( 56\widehat{i}-30\widehat{j}+10\widehat{k} \right ).\left (-20\widehat{i}-15\widehat{j}+7\widehat{k}  \right )

W = -1120 + 450 + 70

W = - 600 J

3 0
3 years ago
A ticker timer makes 50 dots per second. When a body is pulled by a tap through the timer, the distance between the third and fo
fenix001 [56]

Answer:

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Explanation:

The acceleration is defined as the rate of change of velocity.

Here, initial velocity, u = 3/1 = 3 cm/s

final velocity, v = 4/1 = 4 cm/s

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8 0
2 years ago
Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) .
jek_recluse [69]

Explanation:

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cos\theta=\dfrac{0}{50}

\theta=90^{\circ}

6 0
3 years ago
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