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AlexFokin [52]
3 years ago
9

A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the

drill’s angular acceleration. Answer in units of rad/s 2
Physics
1 answer:
mylen [45]3 years ago
4 0

Answer:

Angular acceleration, is 708.07\ rad/s^2

Explanation:

Given that,

Initial speed of the drill, \omega_i=0

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, \omega_f=28940\ rev/min=3030.58\ rad/s

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

\alpha =\dfrac{\omega_f}{t}\\\\\alpha =\dfrac{3030.58\ rad/s}{4.28\ s}\\\\\alpha =708.07\ rad/s^2

So, the drill's angular acceleration is 708.07\ rad/s^2.

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<h3>2,321.62Joules</h3>

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A geneticist looks through a microscope to determine the phenotype of a fruit fly. The microscope is set to an overall magnifica
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f_e = 1.51 cm

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