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tresset_1 [31]
4 years ago
14

Please Help! When a metal is heated, the free electrons gain _____________.

Physics
2 answers:
lakkis [162]4 years ago
7 0
It’s B potential energy
skelet666 [1.2K]4 years ago
6 0

Answer:

When a metal is heated, the free electrons gain

c. kinetic energy

Explanation:

Kinetic energy is an energy possessed  by an object  due to its movement.

Metals contain free electrons  which are called delocalised electrons, they move freely, when a metal is heated they vibrate and  move more quickly - this electrons gain kinetic energy from the excess vibrating ions. They move around thereby transferring some of their energy to the nearby particles

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3 years ago
A car is traveling at 40 m/s. The brakes are applied an after 3 seconds the car is traveling 13 m/s. What is the acceleration of
Elena-2011 [213]

Answer:

- 9m/s²

Explanation:

Given parameters:

Initial velocity  = 40m/s

Time taken  = 3s

Final velocity  = 13m/s

Unknown:

Acceleration of the car  = ?

Solution:

Acceleration is the rate of change of velocity with time taken.

   Acceleration  = \frac{Final velocity  - Initial velocity }{Time taken}  

  Acceleration  = \frac{13  - 40 }{3}   = - 9m/s²

4 0
3 years ago
A uniform cylinder of radius R and mass M is mounted so as to rotate freely about a horizontal axis that is parallel to, and a d
almond37 [142]

Answer:

I = M*(0.5R^2 + h^2)

w = sqrt [2*g*h / (0.5R^2 + h^2)]

Explanation:

Given:

- The radius of the cylinder R

- The mass of the cylinder M

- The distance between horizontal axis h

- The moment of inertia of cylinder I_c

Solution:

- When the axis of rotation and axis with respect to rotation inertia is required do not coincide then we have to apply parallel axis theorem to calculate the moment of inertia about the required axis which is at a distance h from body rotational axis as follows:

                                    I = I_c + M*h^2

- Where I_c of a cylinder is = 0.5*M*R^2

                                    I = 0.5*M*R^2 + M*h^2

                                    I = M*(0.5R^2 + h^2)

- From conservation of total mechanical energy of the cylinder, the change in gravitational potential energy ΔP.E plus the change in kinetic energy ΔK.E of the cylinder must be zero:

                                   ΔP.E = ΔK.E

                                  M*g*h = 0.5*I*w^2

                                  M*g*h = 0.5*M*(0.5R^2 + h^2)*w^2

                                  w^2 = 2*g*h / (0.5R^2 + h^2)

                                  w = sqrt [2*g*h / (0.5R^2 + h^2)]

Where,

             w: The angular speed of the cylinder

8 0
3 years ago
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