"(2) static solution equilibrium" is the type of equilibrium that exists in a sealed flask containing Br2(ℓ) and Br2(g) at 298 K and 1.0 atm.
Answer:
1. 276 g of NO₂
2. 34.8 moles of LiO
3. 4.23×10²⁵ molecules of SO₂
4. 540 g of H₂O
5. 224 g CO
Explanation:
Let's define the molar mass of the compound to define the moles or the grans of each.
Molar mass . moles = Mass
Mass (g) / Molar mass = Moles
1. 6 mol . 46 g / 1 mol = 276 g of NO₂
2. 800 g . 1mol / 22.94 g = 34.8 moles of LiO
3. To determine the number of molecules, we convert the mass to moles and then, we use the NA (1 mol contains 6.02×10²³ molecules)
4500 g . 1mol / 64.06 g = 70.2 moles of SO₂
70.2 mol . 6.02×10²³ molecules / 1 mol = 4.23×10²⁵ molecules of SO₂
4. 30 mol . 18g / 1 mol = 540 g of H₂O
5. 8 mol . 28g / 1mol = 224 g CO
Answer:
Compounds are made of two or more atoms of different elements,
Explanation:
Answer:
Basically it would be 8.5g. Not total sure.
Explanation:
If its right plz give brainlest.
In this case, we are going to assume that there are 100 atoms to make things easier.
Let R% be the abundance of n-15. With this in mind, we calculate the abundance of n-14 to be 100%-R%
14.0031*(100-R)% + 15.001 * R%= 14.00674
In this case, we can delete or ignore the % sign since we do not want to carry it around, however, we need to keep in mind that the final answer is in %
14.0031*(100-R) + 15.001 * R= 14.00674
1400.31-14.0031R+15.001R=1400.674
0.9979R=0.364
R=0.3648
Then, the abundance of n-15 is 0.3648%