According to this formula :
ΔTf= i Kf m
i is van't Hoff factor= 1
Kf = 1.86
m the molality we need to assume it
m= x moles of C2H5OH / Kg of mass
∴ 15 = 1 * 1.86 * ( x moles of C2H5OH/ 0.45 kg)
∴X = 3.629 moles
mass = no.of moles x molar mass of C2H5OH
= 3.629 X 46 = 167 g
∴the volume = mass / denisty
= 167 / 0.7893 = 211.57≈ 212 mL
Answer: Hydroxyl group -OH
Explanation:
This is because the Hydroxyl group has a single atom which can indicate a singlet on the proton Nmr analysis and the value for -OH is around 4 - 5 ppm as well making the unknown functional group to be likely Hydroxyl group
The price would not be a physical property
The molarity of a saline solution that contain 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml solution is 0.15 M
<u><em>calculation</em></u>
Molarity = moles /volume in liters
volume in liters = 100.0 ml / 1000 = 0.1 L
moles = mass÷ molar mass
= 0.900 g ÷58.44 g/mol =0.015 moles
molarity is therefore = 0.015 moles / 0.1 L =0.15 M