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lisov135 [29]
3 years ago
5

You need to make an aqueous solution of 0.216 m manganese(ii) sulfate for an experiment in lab, using a 125 ml volumetric flask.

how much solid manganese(ii) sulfate should you add?
Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
8 0
125 mL= 0.125 L
0.216 M==0.126 mol/L

0.126 mol/L*0.125L=0.0158 mol MnSO4 are needed
Molar mass (MnSO4)= 54.9+32.1+4*16.0= 151 g/mol

 151 g/mol*0.0158 mol=2.39 g solid  MnSO4
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