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sammy [17]
3 years ago
11

When mixing vinegar and baking soda a reaction occurs. What caused the bubbles in the reaction?

Chemistry
2 answers:
Lisa [10]3 years ago
8 0
 <span>The </span>reaction<span> between </span>baking soda<span> and </span>vinegar<span> is used in chemical volcanoes</span>
meriva3 years ago
6 0
Vinegar has acetic acid, and baking soda has sodium bicarbonate. when the two mix it yields carbonic acid and since carbonic unstable it undergoes double displacement which produces carbon dioxide in which the carbon dioxide escapes the sulution as bubbles
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the size of the negative charge of an electron us exactly the same as the size of the positive charge of a proton. what is the o
Ket [755]
Surrounded by a cloud of negatively charged electrons The atomic nucleus consists of positively charged protons and electrically neutral neutrons. (except in the case of Hydrogen-1, which is
154 KB (12,134 words) - 15:57, April 9, 2021
5 0
2 years ago
For the following reaction, calculate how many moles of each product are formed when 4.05 g of water is used.
timurjin [86]

Answer:

A. 0.225 mole of H₂

B. 0.113 mole of O₂.

Explanation:

We'll begin by calculating the number of mole in 4.05 g of water (H₂O). This can be obtained as follow:

Mass of H₂O = 4.05 g

Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mole of H₂O =?

Mole = mass /Molar mass

Mole of H₂O = 4.05 / 18

Mole of H₂O = 0.225 mole

Next, the balanced equation.

2H₂O —> 2H₂ + O₂

From the balanced equation above,

2 moles of H₂O produced 2 moles of H₂ and 1 mole of O₂.

A. Determination of the number of mole hydrogen produced.

From the balanced equation above,

2 moles of H₂O produced 2 moles of H₂.

Therefore, 0.225 mole of H₂O will also produce 0.225 mole of H₂.

B. Determination of the number of mole oxygen produced.

From the balanced equation above,

2 moles of H₂O produced 1 mole of O₂.

Therefore, 0.225 mole of H₂O will produce = (0.225 × 1)/2 = 0.113 mole of O₂.

Thus, 0.113 mole of O₂ is produced.

7 0
3 years ago
ELECTROLYSIS OF MOLTEN NaCl IS DONE IN A DOWNS CELL OPERATING AT 7.0 VOLTS AND 4.0X10^4A. HOW MUCH Na(s) AND Cl2(g) CAN BE PRODU
Greeley [361]

Answer:

Mass of sodium produced = 2.74 × 10⁵ g of Na

Mass of chlorine produce = 4.24 × 10⁵ g of Cl₂

Explanation:

In the electrolysis of molten NaCl as described above, the quantity of charge used is given by the formula, Q = I × t

Where I isnthe current passed in amperes and t is time in seconds.

Q = 4.0 × 10⁴ A × (8 × 60 × 60) s = 1.152 × 10⁹ C

Equation for the discharge of sodium is; Na+ + e- ---> Na (s)

One mole of electrons is required to discharge one mole of Na

One mole of electron = 1 faraday = 96500 C

One mole of Na has a mass of 23 g

96500 C produces 23 g of Na

1.152 × 10⁹ C will produce 23 g × 1.152 × 10⁹ C / 96500 C = 2.74 × 10⁵ g of Na

Equation for the discharge of chlorine gas is; 2 Cl- ---> Cl₂(g) + 2e-

Two mole of electrons are required to discharge one mole of chlorine gas

Two moles of electron = 2 faraday = 2 × 96500 C = 193000

One mole of Cl₂ has a mass of 71 g

193000 C produces 71 g of Cl₂

1.152 × 10⁹ C will produce 71 g × 1.152 × 10⁹ C / 193000 C = 4.24 × 10⁵ g of Cl₂

5 0
3 years ago
2HCl+Ca(OH)2⟶CaCl2+2H2O
RUDIKE [14]
Isn’t it just 3 mols?
5 0
3 years ago
Examine the given reaction. NH4NO3(s) → NH4+(aq) + NO3–(aq) ΔH° = 25.45 kJ/mol ΔS° = 108.7 J/mol·K Which of the given is correct
kobusy [5.1K]

Answer:

B)−6,942 J /mol

Explanation:

At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:

ΔG = ΔH - TΔS

Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.

Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):

ΔG = ΔH - TΔS

ΔG = 25450J/mol - 298K×108.7J/molK

ΔG = -6942.6J/mol

Right solution is:

<h3>B)−6,942 J /mol</h3>

8 0
3 years ago
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