We need to find an equation for each situation. Let x be the number of GB of data used.
Statement 1: At Noise Pollution Cellular, plan A is $30.00 per month and $5.00 for every gigabyte of data used.
Plan A cost equation 
Statement 2: At Noise Pollution Cellular, Plan B is $50.00 per month and $2.00 for every gigabyte of data used.
Plan B cost equation 
Number of GB of data for which both the plan A and plan B cost are <em><u>same</u></em>.
When
When
Answer:
z-3/z+3-z-9/z2+3z
Final result :
3 • (z3 + z2 - z - 3)
———————————
z2
Step-by-step explanation:
Step 1 :
9
Simplify ——
z2
Equation at the end of step 1 :
3 9
((((z-—)+3)-z)-——)+3z
z z2
Step 2 :
3
Simplify —
z
Equation at the end of step 2 :
3 9
((((z - —) + 3) - z) - ——) + 3z
z z2
Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using z as the denominator :
z z • z
z = — = ——
1 z
A = Pe^rt
P = 11,000 ; r = 6.25% ; t = 10 ; e = 2.7183 approximate
A = 11,000 e ^(0.0625 *10)
A = 11,000 e ^0.625
A = 11,000 * 2.7183^0.625
A = 11,000 * 1.868
A = 20,548
A = P (1 + r/n)^nt
P = 11,000 ; r = 6.3% ; n = 2 ; t = 10
A = 11,000 (1 + 0.063/2)^2*10
A = 11,000 (1 + 0.0315)^20
A = 11,000 (1.0315)^20
A = 11,000 (1.859)
A = 20,449
<span>$11,000 invested at 6.25% compounded continuously over 10 years yields the greater return. </span>
Answer:
The correct option is B:
Subtract 2 from both sides
Step-by-step explanation:
We have the equation x²-4x+16=2
The first step to solve this equation is:
Subtract 2 from both sides
We get;
x²-4x+16=2
x²-4x+16-2=2-2
x²-4x+14=0
Now this is the quadratic equation. You can use quadratic formula to solve this equation....
D. both climbers rested on the wall for 2 minutes
