Answer:
Explanation:
Complete question:
A closed-loop conductor that forms a circle with a radius of 2.0 m is located in a uniform but changing magnetic field. If the maximum emf induced in the loop is 5.0 V, what is the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies?
A) 0.40T/s
B) 2.5 T/s
C) 0.080 T/s
D) 5.0 T/s
Answer: A) 0.40T/s
Answer:
v₁ / v₂ = √μ
₂/μ
₁
Explanation:
The speed of a traveling wave on a string is given by
v = √ T /μ
Where v is the speed of the wave, T the tension and μ is the linear density of the string
Let's apply this equation to our case
v₁ = √ T / μ
₁
v2 = √ T /μ
₂
If the voltage of the two systems is the same
T = v₁² μ₁ = v₂² μ₂
We cleared
v₁² / v₂² = μ₂ / μ₁
v₁ / v₂ = √μ
₂/μ
₁
It will experience centripetal accelaration.
Speed = distance / time = 55 / 0.75 = 73.3 miles per hour.
Answer:
a) w = 9.599 10⁴ rad / s
, b) v = 3.35 10¹⁶ m / s
, c) a = 3.22 10²¹ m / s²
Explanation:
For this exercise we must use the relation of angular kinematics
a) angular velocity, the distance remembered in orbit between time (period)
w = 2π r / T
w = 2 π 3.59 10¹¹ / 2.35 10⁷
w = 9.599 10⁴ rad / s
b) linear and angular velocity are related by the equation
v = w r
v = 9,599 10⁴ 3.49 10¹¹
v = 3.35 10¹⁶ m / s
c) the centripetal acceleration is
a = v² / r = w² r
a = (9,599 10⁴)² 3.49 10¹¹
a = 3.22 10²¹ m / s²
