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valina [46]
4 years ago
13

I NEED HELP PLEASE, THANKS :) What does it mean when white light is diffracted and at a particular location the color seen is bl

ue?
Physics
2 answers:
Dvinal [7]4 years ago
8 0

Answer:

When while light is diffracted and at a particular location blue color is seen, this means that blue color is reflected while all other colors will be absorbed. When the blue color is seen denotes the shortest wavelength being reflected and all other being absorbed at the specified location.

alexgriva [62]4 years ago
4 0

Answer:

This is because white light consists of 7 colours with different angles o deviation or retraction.

Explanation:

When a narrow beam of light is refracted by a prism the light spreads into a band of colours (called the spectrum of light )

But in this case if a blue colour is observed it is due to the angle of refraction ,for instance red is refracted the least and hence is seen

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PLEASEE I NEED HELP FAST!!! .Study the scenario.A small container of water with a low temperature is poured into a large contain
RSB [31]

Answer:

that best describes the process is C

Explanation:

This problem is a calorimeter process where the heat given off by one body is equal to the heat absorbed by the other.

Heat absorbed by the smallest container

             Q_c = m ce (T_{f}-T₀)

Heat released by the largest container is

              Q_a = M ce (T_{i}-T_{f})

how

        Q_c = Q_a

       m (T_{f}-T₀) = M (T_{i} - T_{f})

Therefore, we see that the smaller container has less thermal energy and when placed in contact with the larger one, it absorbs part of the heat from it until the thermal energy of the two containers is the same.

Of the final statements, the one that best describes the process is C

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8 0
4 years ago
A heavy flywheel rotating on its central axis is slowing down because of friction in its bearings. At the end of the first minut
Soloha48 [4]

Answer:

ω₂ = 93.6 rev / min

Explanation:

ω₀ = 260 rev / min

ω₁ = 0.68*ω₀ = 0.68*(260 rev / min) = 176.8 rev / min

ω₂ = ?

t₁ = 1 min

t₂ = 2 min

We can apply the equation:

ω₁ = ω₀ + α*t₁     ⇒    α = (ω₁ - ω₀) / t₁  

⇒   α = (176.8 rev / min - 260 rev / min) / 1 min = - 83.2 rev / min²

then we can use the same formula, knowing the angular acceleration:

ω₂ = ω₀ + α*t₂   ⇒   ω₂ = (260 rev / min) + (- 83.2 rev / min²)*(2 min)

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∆x (displacement) = v - u

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Given, the final position of the object is 0 m and the initial position is 5 m.

∆x (displacement) = v - u

= 0 m - 5 m

= -5 m

Therefore, <u>C: -5m</u> is the correct answer.

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