Question

A 210Ω resistor is connected in a circuit with a 110V battery. What total amount of charge passes through a point in the circuit in 2 minutes?

Answer 1

Answer: 62.86 coulombs

Explanation:

Resistance (R) = 210Ω

Voltage of battery (V) = 110V

total amount of charge (Q) = ?

Time (T) = 2 minutes

The SI unit of time is seconds so convert 2 minutes to seconds

(If 1 minute = 60 seconds

2 minutes = 2 x 60 = 120 seconds)

To get the total charge, first get the current (I) flowing in the circuit by applying the formula V = IR

110V = I x 210Ω

I = 110V/210Ω

I = 0.524 Amps

Then, apply the formula

Charge = current x time

i.e Q = IT

Q = 0.524 Amps x 120 seconds

Q = 62.86 coulombs

Thus, 62.86 coulombs of charge passes through the circuit.