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agasfer [191]
3 years ago
14

A cylindrical capacitor is being charged by an exponentially decreasing current. The inner cylinder of the capacitor is positive

and the outer cylinder is negative. What is the direction of the magnetic field between the two cylinders while the capacitor is charging
Physics
1 answer:
lisov135 [29]3 years ago
8 0

The direction of the magnetic field between the two cylinders while the capacitor is charging is counterclockwise.

According to Maxwell's law of induction, a changing electric field induces a magnetic field, B given by the equation

∫B.ds = μεdΦ/dt where ds = path length of magnetic field, μ = permeability of free space, ε = permittivity of free space and dΦ/dt = rate of change in electric flux. The electric field in the cylindrical capacitor is directed from the inner cylinder to the outer cylinder since the inner cylinder is positive and outer cylinder negative.

For an electric current which increases, the rate of change of electric flux is positive and this produces a magnetic field in the clockwise direction.

Since in this case, we have an exponentially decreasing current, dΦ/dt is negative. Thus, this will produce a magnetic field opposite to that of an increasing current. So, the direction of the magnetic field would be counter clockwise.

So, the direction of the magnetic field between the two cylinders while the capacitor is charging is counterclockwise.

Learn more about Maxwell's law of induction here:

brainly.com/question/4363096

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4 years ago
Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic colli
Pie

Answer:

a)  v = 3,843 m / s, b)  46.7º  North- East

Explanation:

Moment is a vector quantity, so one of the best ways to solve this problem is to solve each component separately.

The system is formed by the two vehicles so that the moment is preserved during the crash

Direction to the East    

initial instant. Before the crash

          p₀ = mₐ vₐ₀

final insttne. After the crash

          p_f = (mₐ + m_b) vₓ

         p₀ = p_f

         mₐ vₐ₀ = (mₐ + m_b) vₓ

         vₓ = \frac{m_a}{m_a + m_b} \ v_{ao}

let's calculate

          vₓ = \frac{16.7}{16.7 + 29.3} \ 7.26

          vₓ = 2,636 m / s

direction north

initial   p₀ = m_b v_{bo}

final     p_f = (mₐ + m_b) v_y

          p₀ = p_f

          m_b v_{bo} = (mₐ + m_b) v_y

          v_y = \frac{m_b}{m_a+m_b} \ v_{bo}

let's calculate

          v_y = \frac{29.3}{16.7 + 29.3} \ 4.39

          v_y = 2.796 m / s

the final speed of the two two vehicles is

          v = (2,636 i ^ + 2,796 j ^) m / s

a) the magnitude of the velocity

let's use the Pythagorean theorem

       v = \sqrt{v_x^2 + v_y^2}

      v = \sqrt{2.636^2 + 2.796^2}

      v = 3,843 m / s

b) let's use trigonometry to find the direction

      tan θ = v_y / vₓ

      θ = tan⁻¹ v_y / vₓ

      θ = tan⁻¹ (2,796 / 2,636)

      θ = 46.7º

This direction is 46.7º  North East

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The Electron Cloud Model shows shaded regions of probabilty where the electons most likely are at a given point in time. True Fa
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Answer:

True

Explanation:

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After watching this video, Blake, a student in an introductory physics class, makes the following claim: The acceleration and ve
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Answer:

Please see below as the answer is self- explanatory.

Explanation:

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Mass of the vehicle = 2000 kg
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Radius of the curve = 80 m
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